为什么我会得到PLS - 00382？

Question

这里是我的对象DEF：

CREATE OR REPLACE TYPE FALCON.contacts AS OBJECT (phone   VARCHAR2(50) 
    ,phoneusage  VARCHAR2(25) 
    ,phonetype  VARCHAR2(25) 
    ,email   VARCHAR2(150) 
    ,phoneext  VARCHAR2(25) 
    ,anytext   VARCHAR2(250)) 

下面是表DEF：

CREATE OR REPLACE TYPE FALCON.contacttbl AS TABLE OF contacts 

这里是我的管道函数

FUNCTION get_pcontacts(p_conttbl IN xmltypedefs_spec.conttbl) 
RETURN falcon.contacttbl 
PIPELINED 
IS 
    l_contact falcon.contacts; 
BEGIN 
    FOR n IN 1 .. p_conttbl.count 
    LOOP 
     PIPE ROW(**falcon.contacts**(p_conttbl(n).phone, p_conttbl(n).phoneusage,    p_conttbl(n).phonetype, p_conttbl(n).email, p_conttbl(n).phoneext, p_conttbl(n).anytext)); 
    END LOOP; 
    RETURN; 
END get_pcontacts; 

我得到的错误，当我调用表功能：

FUNCTION get_pidxml(p_pidrec xmltypedefs_spec.pidtyp) 
RETURN CLOB 
IS 
    l_tmprec     CLOB; 
    l_pxml     xmltype; 
    l_bxml     xmltype; 
    l_pcontacts    xmltypedefs_spec.conttbl := p_pidrec.personalcont; 
    l_bcontacts    xmltypedefs_spec.conttbl := p_pidrec.businesscont; 

BEGIN 

--  l_pxml := get_contacts(p_pidrec, 'p'); 
--  l_bxml := get_contacts(p_pidrec, 'b'); 

SELECT xmlelement("pid" 
        ,xmlforest(p_pidrec.setid AS "setID" 
           ,p_pidrec.patidexternal AS "patientIDExternal" 
           ,p_pidrec.patientid AS "patientID" 
           ,p_pidrec.patintasgnauth AS "patientIDInterAssignAuthority" 
           ,p_pidrec.patinttypecd AS "patientIDInternalIDTypeCode" 
           ,p_pidrec.patidalternate1 AS "patientIDAlernate1" 
           ,p_pidrec.patlastname AS "patientLastName" 
           ,p_pidrec.patfirstname AS "patientFirstName" 
           ,p_pidrec.patmiddleinit AS "patientMiddleInitial" 
           ,p_pidrec.patsuffix AS "patientSuffix" 
           ,p_pidrec.patprefix AS "patientPrefix" 
           ,p_pidrec.degree AS "degree" 
           ,p_pidrec.familyname AS "familyName" 
           ,p_pidrec.givenname AS "givenName" 
           ,p_pidrec.mothermaidname AS "mothersMaidenName" 
           ,p_pidrec.dob AS "dateOfBirth" 
           ,p_pidrec.adminsex AS "administrativeSex" 
           ,p_pidrec.patientalias AS "patientAlias" 
           ,p_pidrec.race AS "race" 
           ,p_pidrec.racetext AS "raceText" 
           ,p_pidrec.pataddr1 AS "patientAddress1" 
           ,p_pidrec.pataddr2 AS "patientAddress2" 
           ,p_pidrec.patcity AS "patientCity" 
           ,p_pidrec.patstate AS "patientState" 
           ,p_pidrec.patzip AS "patientZip" 
           ,p_pidrec.countrycode AS "countryCode" 
           ,p_pidrec.addresstype AS "addressType" 
           ,p_pidrec.othgeodesig AS "otherGeographicDesignation" 
           ,p_pidrec.county AS "county" 

           ,(SELECT xmlagg(xmlelement("contactInfo", 
              xmlforest(phone AS "phoneNumber", 
                 phoneusage AS "telecomUseCode", 
                 phonetype AS "telecomequiptype", 
                 email AS "email", 
                 phoneext AS "phonenumberextension", 
                 anytext AS "anytext"))) 
           FROM TABLE(**get_pcontacts(l_pcontacts**))) AS "personalContact" 

Answer 1

http://pls-00382.ora-code.com/

PLS-00382：表达式类型错误

的因为我不知道xmltypedefs_spec.conttbl是如何定义的呢，我删除从管道函数的输入参数，只是有它产生假数据飞：

CREATE OR REPLACE FUNCTION get_contacts 
    RETURN contacttbl PIPELINED 
IS 
    -- converts some structure to pipe of contacts 
BEGIN 
    FOR n IN 1 .. 5 LOOP 
     PIPE ROW( 
     contact( 
      '877-867-5309', 
      'Work', 
      'Cell', 
      'jenny@gmail.com', 
      n, 
      'WTF?' 
     ) 
    ); 
    END LOOP; 
    RETURN; 
END get_contacts; 

的查询现在执行没有错误：

SELECT 
    xmlagg(
     xmlelement("contactInfo", 
      xmlforest(
       phone AS "phoneNumber", 
       phoneusage AS "telecomUseCode", 
       phonetype AS "telecomequiptype", 
       email AS "email", 
       phoneext AS "phonenumberextension", 
       anytext AS "anytext" 
      ) 
     ) 
    ) 
FROM 
    TABLE(get_contacts()) 

这告诉我可能xmltypedefs_spec.conttbl有问题，也许在SQL语句中使用集合类型？不确定。如果将xmltypedefs_spec.pidtyp更改为使用falcon.contacttbl而不是xmltypedefs_spec.conttbl，会怎么样？似乎你有一个包类型和一个对象类型正在做同样的事情？

Answer 2

xmltypedefs_spec定义对应于XML元素的记录类型。这些记录类型用于碎化和构建XML。最初，XML不使用重复元素，但现在必须。我试图获取一个xmltypedefs_spec.pidtyp表，并使用流水线函数从关联表中返回'行'的数据。正是以这种方式，我想发送数组记录的行来构建xml。