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我有一个任务来编写一个应用程序,该应用程序将接受来自用户的输入,并将每个答案存储在一个字符串数组中。此应用程序还必须检查用户输入的空值,并重新提示用户输入其答案。应用程序必须只重复空白的问题,因为这个应用程序有50个问题。循环检查用户输入的空白空间
这是到目前为止我的代码:
for(iLoop=0; iLoop<noOfQuest; iLoop++)
{
if(noOfEmails<1)
{
System.out.println("FILE_ERROR: Please ensure line \"noOfEmails\" is more than 0");
}
if(noOfQuest==1)
{
System.out.println(prefinalMess);
System.out.println(questionArr[0]);
ansArray[iLoop]=ans.next();
System.out.println(finalMess);
}
if(noOfQuest==2)
{
System.out.println(questionArr[0]);
ansArray[iLoop]=ans.next();
System.out.println(prefinalMess);
System.out.println(questionArr[1]);
ansArray[iLoop]=ans.next();
System.out.println(finalMess);
}
if(noOfQuest==3)
{
System.out.println(questionArr[0]);
ansArray[iLoop]=ans.next();
System.out.println(questionArr[1]);
ansArray[iLoop]=ans.next();
System.out.println(prefinalMess);
System.out.println(questionArr[2]);
ansArray[iLoop]=ans.next();
System.out.println(finalMess);
}
if(noOfQuest==4)
{
System.out.println(questionArr[0]);
ansArray[iLoop]=ans.next();
System.out.println(questionArr[1]);
ansArray[iLoop]=ans.next();
System.out.println(questionArr[2]);
ansArray[iLoop]=ans.next();
System.out.println(prefinalMess);
System.out.println(questionArr[3]);
ansArray[iLoop]=ans.next();
System.out.println(finalMess);
}
if(noOfQuest==5)
{
System.out.println(questionArr[0]);
ansArray[iLoop]=ans.next();
System.out.println(questionArr[1]);
ansArray[iLoop]=ans.next();
System.out.println(questionArr[2]);
ansArray[iLoop]=ans.next();
System.out.println(questionArr[3]);
ansArray[iLoop]=ans.next();
System.out.println(prefinalMess);
System.out.println(questionArr[3]);
ansArray[iLoop]=ans.next();
System.out.println(finalMess);
}
}
我还必须开发新方法来检查每个答案的输入。
非常感谢,让我当涉及到添加更多问题时,工作更容易:3 – 2015-02-10 14:50:02