添加到XML模式的引用，XML序列化输出

Question

当序列化对象的代码：

var xmlSerializer = new XmlSerializer(typeof(MyType)); 
using (var xmlWriter = new StreamWriter(outputFileName)) 
{ 
    xmlSerializer.Serialize(xmlWriter, myTypeInstance); 
} 

在输出XML文件获取：

<MyType xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 

如何添加引用XML架构，所以它看起来像这样：

<MyType xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
     xsi:noNamespaceSchemaLocation="mySchema.xsd"> 

Answer 1

[编辑]

您可以显式实现IXmlSerializable并自己写入/读取xml。

public class MyType : IXmlSerializable 
{ 
    void IXmlSerializable.WriteXml(XmlWriter writer) 
    { 
     writer.WriteAttributeString("xmlns:xsd", "http://www.w3.org/2001/XMLSchema"); 
     writer.WriteAttributeString("xsi", "noNamespaceSchemaLocation", XmlSchema.InstanceNamespace, "mySchema.xsd"); 

     // other elements & attributes 
    } 

    XmlSchema IXmlSerializable.GetSchema() 
    { 
     throw new NotImplementedException(); 
    } 

    void IXmlSerializable.ReadXml(XmlReader reader) 
    { 
     throw new NotImplementedException(); 
    } 
} 

xmlSerializer.Serialize(xmlWriter, myTypeInstance); 

最有可能不是一个理想的解决方案，但添加下面的字段和属性到你的类将做的伎俩。

public class MyType 
{ 
    [XmlAttribute(AttributeName="noNamespaceSchemaLocation", Namespace="http://www.w3.org/2001/XMLSchema-instance")] 
    public string Schema = @"mySchema.xsd"; 
} 

另一种选择是创建您自己的自定义XmlTextWriter类。

xmlSerializer.Serialize(new CustomXmlTextWriter(xmlWriter), myTypeInstance); 

或者不使用序列化

var xmlDoc = new XmlDocument(); 
xmlDoc.AppendChild(xmlDoc.CreateXmlDeclaration("1.0", "utf-8", null)); 

var xmlNode = xmlDoc.CreateElement("MyType"); 
xmlDoc.AppendChild(xmlNode); 

xmlNode.SetAttribute("xmlns:xsi", "http://www.w3.org/2001/XMLSchema-instance"); 
xmlNode.SetAttribute("xmlns:xsd", "http://www.w3.org/2001/XMLSchema"); 

var schema = xmlDoc.CreateAttribute("xsi", "noNamespaceSchemaLocation", "http://www.w3.org/2001/XMLSchema-instance"); 
schema.Value = "mySchema.xsd"; 
xmlNode.SetAttributeNode(schema); 

xmlDoc.Save(...); 

希望这有助于...