阅读文本文件分成几个列表一行行

Question

如果我们有一个文本文件，如下所示：

６ & ロク３ & サン 
９ & キュウ 
０ & ゼロ５ & ゴ 
７ & ナナみぎ & ミギひだり & ヒダリ 
うえ & ウエ 

一个人怎么能读入蟒蛇得到一个列表的方式，每个“列”像这样的：

a = ["6", "9", "0", "7", "うえ"] 
b = ["ロク３" , "キュウ", "ゼロ５", "ナナみぎ", "ウエ"] 
c = ["サン", "", "ゴ}", "ミギひだり", ""] 
d = ["", "ヒダリ", "", "", ""] 

Answer 1

尝试了这一点：

with open(path, 'r') as inputFile: 
    lines = list() 

    for line in inputFile: 
     lines.append(line.split("&")) 

    maxLen = len(max(lines, key=lambda x: len(x))) 

    for line in lines: 
     while len(line) < maxLen: 
      line.append(" ") 

    column0 = [line[0] for line in lines] 
    column1 = [line[1] for line in lines] 
    . 
    . 
    . 

另外，如果你想在“细胞”摆脱空白的，使用replace方法：

without_spaces = with_spaces.replace(" ", "") 

要使用它，只需更换

lines.append(line.split("&")) 

与

lines.append(line.replace(" ", "").split("&")) 

Answer 2

itertools.izip_longest将是任务非常方便。

import itertools 

def cleanup(alist): 
    return [item.strip() for item in alist] 

with open('input.txt', 'r') as input_file: 
    lines = input_file.readlines() 
    contents = [cleanup(line.split('&')) for line in lines] 
    zipped = itertools.izip_longest(*contents, fillvalue='') 

    for column in zipped: 
     print column 

请注意zipped实际上是所有列的迭代器。