1
我实现可折叠,数据结构如下:暧昧发生 'foldMap'
data Tree a = Leaf a | Node (Tree a) (Tree a) deriving Show
当我执行倍和foldMap:
instance Foldable Tree where
--fold :: Monoid a => Tree a -> a
fold (Leaf x) = x
fold (Node l r) = fold l `mappend` fold r
--foldMap :: Monoid b => (a -> b) -> Tree a -> b
foldMap f (Leaf x) = f x
foldMap f (Node l r) = foldMap f l `mappend` foldMap f r
我会收到以下错误:
Ambiguous occurrence ‘foldMap’
It could refer to either ‘Main.foldMap’,
defined at Chapterh14.hs:57:1
or ‘Prelude.foldMap’,
imported from ‘Prelude’ at Chapterh14.hs:1:1
(and originally defined in ‘Data.Foldable’)
Chapterh14.hs:58:46:
Ambiguous occurrence ‘foldMap’
It could refer to either ‘Main.foldMap’,
defined at Chapterh14.hs:57:1
or ‘Prelude.foldMap’,
imported from ‘Prelude’ at Chapterh14.hs:1:1
(and originally defined in ‘Data.Foldable’)
Chapterh14.hs:71:13:
Ambiguous occurrence ‘foldMap’
It could refer to either ‘Main.foldMap’,
defined at Chapterh14.hs:57:1
or ‘Prelude.foldMap’,
imported from ‘Prelude’ at Chapterh14.hs:1:1
(and originally defined in ‘Data.Foldable’)
当我删除foldMap的定义时,我将得到以下警告:
No explicit implementation for
either ‘foldMap’ or ‘foldr’
In the instance declaration for ‘Foldable Tree’
Ok, modules loaded: Main.
当我实现函数时,我会得到它已经存在的错误,但是当我没有实现该函数时,我会得到一个警告,表明函数丢失了?我究竟做错了什么?
“为什么这是一个警告,而不是我不知道的错误” - 好点。也许这是因为每种方法都有一个默认定义?通常,通过这样的默认值是相互递归的,并且除非用户定义了某种方法,否则会简单地发生分歧。例如。 'Eq'有'==,/ ='默认,但是至少需要定义其中的一个才能正常工作。 – chi
@chi它看起来总是一个警告,即使缺少的函数没有默认实现。 '实例Functor Foo where {}'只产生一个警告。我相信肯定有一个很好的理由... –
@BenjaminHodgson我不确定你是否称它为“好”的理由,但偶尔你想使用一个思想不深的类(' Num',我在看着你......),尽管一些方法对你的类型没有完全意义。在这种情况下,默认的默认实现(不是错字 - 它是编译器为您编写的默认实现)调用'error'会很方便。 –