PowerShell - 为什么某些请求类型不起作用？

Question

这太奇怪了吧。对于HTTP的那些和https出现很好..端口8080和8443的那些不..

$ip="1.2.3.4" 
$urls = "http://$ip","http://"$ip":8080","https://$ip","https://"$ip":8443" 
foreach ($u in $urls) 
{ 
"$u" 
} 

结果表明：

PS C:\Documents and Settings\user> D:\WORK\ps\test.ps1 
Unexpected token 'ip' in expression or statement. 
At D:\WORK\ps\test.ps1:2 char:37 
+ $rsaurls = "http://$ip","http://"$ip <<<< ":8080","https://$ip","https://"$ip":8443" 
    + CategoryInfo   : ParserError: (ip:String) [], ParentContainsErrorRecordException 
    + FullyQualifiedErrorId : UnexpectedToken 

如果我们删除了报价..

$ip="1.2.3.4" 
$urls = "http://$ip","http://$ip:8080","https://$ip","https://$ip:8443" 
foreach ($u in $urls) 
{ 
"$u" 
} 

And the results show: 
PS C:\Documents and Settings\user> D:\WORK\ps\test.ps1 
http://1.2.3.4 
http:// 
https://1.2.3.4 
https:// 

我想我需要逃避 “：” ..

个我仔细..

$ip="1.2.3.4" 
$urls = "http://$ip","http://$ip^:8080","https://$ip","https://$ip^:8443" 
foreach ($u in $urls) 
{ 
"$u" 
} 

，结果：

PS C:\Documents and Settings\user> D:\WORK\ps\test.ps1 
http://1.2.3.4 
http://1.2.3.4^:8080 
https://1.2.3.4 
https://1.2.3.4^:8443 

谢谢！

Answer 1

我相信PowerShell是解释$ip:8080作为其范围是 “IP”，并将其命名为 “8080” 的变量。使用大括号来说明变量名称：

"https://${ip}:8080" 

Answer 2

好..用'角色逃脱吧！

$ip="1.2.3.4" 
$urls = "http://$ip","http://$ip`:8080","https://$ip","https://$ip`:8443" 
foreach ($u in $urls) 
{ 
"$u" 
} 

，结果：

PS C:\Documents and Settings\user> D:\WORK\ps\test.ps1 
http://1.2.3.4 
http://1.2.3.4:8080 
https://1.2.3.4 
https://1.2.3.4:8443