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我有一个50x50的像素空间,其中需要绘制五条线:X和Y轴,以及steepest
,average
和flattest
中的每一个斜线。在狭窄的空间中绘制斜线
我正在使用(Java)代码,这是传给我没有任何文档或评论,我从来没有在画布上绘制过。这是一个175x75像素的盒子的代码。如上所述,这需要适应50x50的区域。
DrawingArea canvas = new DrawingArea(175, 75);
canvasContainer.add(canvas);
Rectangle rectangle = new Rectangle(0, 0, 174, 75);
canvas.add(rectangle);
Line slopeMainLineX = new Line(5, 70, 170, 70);
slopeMainLineX.setStrokeOpacity(0.5);
canvas.add(slopeMainLineX);
Line slopeMainLineY = new Line(40, 70, 40, 0);
slopeMainLineY.setStrokeOpacity(0.5);
canvas.add(slopeMainLineY);
steepestLine = new Line(40, 70, 0, 0);
steepestLine.setStrokeWidth(3);
canvas.add(steepestLine);
avgSlopeLine = new Line(40, 70, 0, 0);
avgSlopeLine.setStrokeWidth(2);
canvas.add(avgSlopeLine);
flattestLine = new Line(40, 70, 0, 0);
flattestLine.setStrokeWidth(1);
canvas.add(flattestLine);
int steepestAngle = Math.round(site.getSlope().getMax());
int averageAngle = Math.round(site.getSlope().getAvg());
int flatestAngle = Math.round(site.getSlope().getMin());
double xPointSteepestAngle = 40 + 120 * Math.cos(steepestAngle*0.0174532925);
double yPointSteepestAngle = 70 + 120 * Math.sin(steepestAngle*0.0174532925);
double xPointAverageAngle = 40 + 120 * Math.cos(averageAngle*0.0174532925);
double yPointAverageAngle = 70 + 120 * Math.sin(averageAngle*0.0174532925);
double xPointFlatestAngle = 40 + 120 * Math.cos(flatestAngle*0.0174532925);
double yPointFlatestAngle = 70 + 120 * Math.sin(flatestAngle*0.0174532925);
steepestLine.setX2((int) xPointSteepestAngle);
steepestLine.setY2(70 - ((int) yPointSteepestAngle - 70));
avgSlopeLine.setX2((int) xPointAverageAngle);
avgSlopeLine.setY2(70 - ((int) yPointAverageAngle - 70));
flatestLine.setX2((int) xPointFlatestAngle);
flatestLine.setY2(70 - ((int) yPointFlatestAngle - 70));
我完全失去了这里,所以任何帮助将不胜感激。
原谅我,我显然忘了提及这是使用GWT的DrawingArea作为画布。您引用的命令对于此控件不存在。 –
Ooooh,对不起。我以为你使用的是HTML5 Canvas。实际上GWT中有更接近你的命令的等价物。看到这里:http://code.google.com/p/gwt-graphics/wiki/Manual 让事情像一条线几乎完全相同 –
感谢您的帮助。 –