2013-07-10 38 views
0

我构建了一个非常基本的webAPI,它在被调用时在屏幕上打印一些json数据。当URL包含数据时,没有返回json数据

我打电话跟以下

function getEnvironmentList(){ 
    $fullUrl = "localhost/serverList/api/rest.php?action=allenvironments&format=json"; 
    $jsonDataRaw = file_get_contents($fullUrl); 
    return $jsonDataRaw; 
} 
$jsonData = getEnvironmentList(); 
echo "<PRE>"; 
var_dump(json_decode($jsonData, true)); 
echo "</PRE>"; 

我得到的错误Warning: file_get_contents(localhost/serverList/api/rest.php?action=allenvironments&format=json): failed to open stream: No error in C:\path\inc\getJSONdata.php on line 6

然而,当我访问该网址我看到这个

{"1":{"environmentID":"1","envName":"UAT","envCreatedBy":"mhopkins","envCreatedDtTm":"2013-06-30 00:34:57","envUpdatedBy":"mhopkins","envUpdatedDtTm":"2013-06-30 00:34:57"},"3":{"environmentID":"3","envName":"Platinum","envCreatedBy":"mhopkins","envCreatedDtTm":"2013-06-30 00:37:38","envUpdatedBy":"phpsense","envUpdatedDtTm":"2013-06-30 00:37:38"}} 

我真的很困惑的API为什么代码似乎无法实现那里有json数据...

回答

3

你忘了http

$fullUrl = "http://localhost/serverList/api/rest.php?action=allenvironments&format=json"; 
+0

是的,就是这样。我想我只是想知道如果我可以复制/粘贴它并查看数据,计算机也可以。 PHP很挑剔!谢谢! – mhopkins321

+0

完美。请考虑将答案标记为正确答案。谢谢。 –

+1

倒计时时间为11分钟。我会一旦达到0 – mhopkins321