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我正在从XML文档读取DMX值。该方法只返回一个节点上，而我试图从拉动因素，但应该有512为什么此Java方法不返回所有XML元素？
这里是方法：
public static void readXML(int cueNo){
try {
File fXmlFile = new File(MixWindow.Globals.fileLoc);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("Cue");
System.out.println("-----------------------");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = (Node) nList.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("Cue Name : " + getTagValue("Cue_Name", eElement));
System.out.println("Cue Number : " + getTagValue("Cue_Number", eElement));
//System.out.println("Nick Name : " + getTagValue("nickname", eElement));
//System.out.println("Salary : " + getTagValue("salary", eElement));
}
}
NodeList nListII = doc.getElementsByTagName("DMX");
//nListII = doc.getElementsByTagName("DMX");
System.out.println("-----------------------");
int length = nListII.getLength();
System.out.println("DMX Length: " + length);
for (int tempII = 0; tempII < nListII.getLength(); tempII++) {
Node nNodeII = (Node) nListII.item(tempII);
if (nNodeII.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNodeII;
System.out.println("DMX Chnl: " + getTagValue("DMX_Chnl", eElement));
System.out.println("DMX Val: " + getTagValue("DMX_Val", eElement));
//System.out.println("Nick Name : " + getTagValue("nickname", eElement));
//System.out.println("Salary : " + getTagValue("salary", eElement));
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
private static String getTagValue(String sTag, Element eElement) {
NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes();
Node nValue = (Node) nlList.item(0);
return nValue.getNodeValue();
}
}
下面是XML文件的一部分：
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<ShowFile>
<Cue>
<Cue_Name>stuff and junk</Cue_Name>
<Cue_Number>1</Cue_Number></Cue>
<DMX>
<DMX_Chnl>1</DMX_Chnl>
<DMX_Val>0</DMX_Val>
<DMX_Chnl>2</DMX_Chnl>
<DMX_Val>0</DMX_Val>
<DMX_Chnl>3</DMX_Chnl>
<DMX_Val>0</DMX_Val>
<DMX_Chnl>4</DMX_Chnl>
<DMX_Val>0</DMX_Val>
......
<DMX_Chnl>512</DMX_Chnl>
<DMX_Val>0</DMX_Val>
的System.out创造了这个：
Cue Name : stuff and junk
Cue Number : 1
-----------------------
DMX Length: 1
DMX Chnl: 1
DMX Val : 0
我在做什么错？
缩短XML：
<?xml version="1.0" encoding="UTF-8" standalone="no"?><ShowFile><Cue><Cue_Name>Stuff and Junk</Cue_Name><Cue_Number>1</Cue_Number></Cue><DMX><DMX_Chnl>1</DMX_Chnl><DMX_Val>0</DMX_Val><DMX_Cue>1</DMX_Cue><DMX_Chnl>2</DMX_Chnl><DMX_Val>0</DMX_Val><DMX_Cue>1</DMX_Cue><DMX_Chnl>3</DMX_Chnl><DMX_Val>0</DMX_Val><DMX_Cue>1</DMX_Cue><DMX_Chnl>4</DMX_Chnl></DMX></ShowFile>
添加循环：
if (nNodeII.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNodeII;
NodeList childNodes = nNodeII.getChildNodes();
String result = new String();
for (int i = 0; i < childNodes.getLength(); i++) {
Node node = childNodes.item(i);
String dcName = node.getNodeName();
String dcVal = node.getNodeValue();
System.out.println("DMX stuff: " + dcName + " " + dcVal);
}
}
可以缩短你的XML文件，并提供完整的缩短Xml和其输出吗？目前，我无法确定第二次提到'Cue Name'和'Cue Number'来自哪里？如果我正确地得到你的代码，为了实现这个目标，你的Xml文档中必须有几个''元素，对吧？ –
从您的XML看起来您有512个DMX_Chnl和512个DMX_Val元素，但只有一个DMX。 – mazaneicha