Java ME实用功能

Question

JavaME在功能上相当稀疏。请列出您最喜欢的实用程序函数，使其更像使用适当的Java，每个答案一个。尝试使您的答案专用于Java ME。

Answer 1

将字符串分割

static public String[] split(String str, char c) 
{ 
    int l=str.length(); 
    int count = 0; 
    for(int i = 0;i < l;i++) 
    { 
     if (str.charAt(i) == c) 
     { 
     count ++;  
     } 
    } 
    int first = 0; 
    int last = 0; 
    int segment=0; 
    String[] array = new String[count + 1]; 
    for(int i=0;i<l;i++) 
    { 
     if (str.charAt(i) == c) 
     { 
      last = i; 
      array[segment++] = str.substring(first,last); 
      first = last; 

     } 
     if(i==l-1){ 
      array[segment++] = str.substring(first,l); 
     } 
    } 
    return array; 
} 

Answer 2

阅读从一个读者的线。另见this question。

public class LineReader{ 
private Reader in; 
private int bucket=-1; 
public LineReader(Reader in){ 
    this.in=in; 
} 

    public boolean hasLine() throws IOException{ 
    if(bucket!=-1)return true; 
    bucket=in.read(); 
    return bucket!=-1; 
    } 

//Read a line, removing any /r and /n. Buffers the string 
public String readLine() throws IOException{ 
    int tmp; 
    StringBuffer out=new StringBuffer(); 
    //Read in data 
    while(true){ 
    //Check the bucket first. If empty read from the input stream 
    if(bucket!=-1){ 
    tmp=bucket; 
    bucket=-1; 
    }else{ 
    tmp=in.read(); 
    if(tmp==-1)break; 
    } 
    //If new line, then discard it. If we get a \r, we need to look ahead so can use bucket 
    if(tmp=='\r'){ 
    int nextChar=in.read(); 
    if(tmp!='\n')bucket=nextChar;//Ignores \r\n, but not \r\r 
    break; 
    }else if(tmp=='\n'){ 
    break; 
    }else{ 
    //Otherwise just append the character 
    out.append((char) tmp); 
    } 
    } 
    return out.toString(); 
} 
} 

Answer 3

小日志框架

微测井 http://microlog.sourceforge.net/site/