MYSQL设计查询问题

Question

我想创建一个查询，显示所有发生罚款但没有驾驶执照的人的姓名和地址。 （所以不要出现在驾驶执照表中）我将如何处理包括没有出现在表格中的东西？

这里是我的表

CREATE TABLE offences (
oOffenceID VARCHAR (30), 
oDescription VARCHAR (200), 
oMaximumFine INT (10), 
CONSTRAINT o_pk 
PRIMARY KEY (oOffenceID) 
); 

CREATE TABLE drivers (
dPersonID VARCHAR (30), 
dLicenseNumber INT (20), 
dLicenseRemoved ENUM('yes','no'), 
dExpiryDate DATE, 
CONSTRAINT d_pk 
PRIMARY KEY (dLicenseNumber), 
CONSTRAINT d_fk 
FOREIGN KEY (dPersonId) 
REFERENCES People (pPersonID) 
); 

CREATE TABLE people (
pPersonID VARCHAR (30), 
pName VARCHAR (30), 
pAddress VARCHAR (50), 
pNIN VARCHAR (30), 
CONSTRAINT p_pk 
PRIMARY KEY (pPersonID) 
); 

CREATE TABLE vehicle (
vOwnerID VARCHAR (30), 
vColour VARCHAR (30), 
vModel VARCHAR (30), 
vMake VARCHAR (30), 
vVehicleID VARCHAR (30), 
CONSTRAINT v_pk 
PRIMARY KEY (vVehicleID), 
CONSTRAINT v_fk 
FOREIGN KEY (vOwnerID) 
REFERENCES People (pPersonID) 
); 

CREATE TABLE fines (
fFineID INT (30) AUTO_INCREMENT, 
fVehicleID VARCHAR (30), 
fPersonID VARCHAR (30), 
fTime DATE, 
fAmount INT (10), 
fOfficerStatement VARCHAR (500), 
fOffenceID VARCHAR (30), 
CONSTRAINT f_pk 
PRIMARY KEY (fFineID), 
CONSTRAINT f_fk 
FOREIGN KEY (fVehicleID) 
REFERENCES vehicle (vVehicleID), 
CONSTRAINT f_fk1 
FOREIGN KEY (fPersonID) 
REFERENCES people (pPersonID), 
CONSTRAINT f_fk2 
FOREIGN KEY (fOffenceID) 
REFERENCES offences (oOffenceID) 
); 

到目前为止，我有

SELECT DISTINCT pName, pAddress 
FROM people, fines, drivers 
WHERE 
pPersonID <> dPersonID 
AND 
pPersonID = fPersonID 
AND 
fAmount > 0 

但这不会删除所有必要的数据。 任何帮助或指导正确的工具使用将不胜感激。

Answer 1

使用LEFT JOIN和检查NULL值

例如：

SELECT * 
FROM 
table_A 
LEFT JOIN table_B 
ON table_A.id = table_b.a_id 
WHERE table_B.a_id IS NULL