0
有人可以给我提示,在lucene中应用伪反馈。我无法在Google上找到太多帮助。我正在使用相似性类。 在lucene中是否有任何类可以扩展来实现反馈? 谢谢。在lucene中实现反馈
有人可以给我提示,在lucene中应用伪反馈。我无法在Google上找到太多帮助。我正在使用相似性类。 在lucene中是否有任何类可以扩展来实现反馈? 谢谢。在lucene中实现反馈
假设你指的是this relevance feedback method,一旦你有原始查询的TopDocs
,迭代你想要的记录的数量(假设我们想要原始查询的前25个文档的前25项) ,并致电IndexReader.getTermVectors(int)
,这将抓住你需要的信息。遍历每个。而在哈希映射中存储术语频率将是我立即发生的实现。
喜欢的东西:
//Get the original results
TopDocs docs = indexsearcher.search(query,25);
HashMap<String,ScorePair> map = new HashMap<String,ScorePair>();
for (int i = 0; i < docs.scoreDocs.length; i++) {
//Iterate fields for each result
FieldsEnum fields = indexreader.getTermVectors(docs.scoreDocs[i].doc).iterator();
String fieldname;
while (fieldname = fields.next()) {
//For each field, iterate it's terms
TermsEnum terms = fields.terms().iterator();
while (terms.next()) {
//and store it
putTermInMap(fieldname, terms.term(), terms.docFreq(), map);
}
}
}
List<ScorePair> byScore = new ArrayList<ScorePair>(map.values());
Collections.sort(byScore);
BooleanQuery bq = new BooleanQuery();
//Perhaps we want to give the original query a bit of a boost
query.setBoost(5);
bq.add(query,BooleanClause.Occur.SHOULD);
for (int i = 0; i < 25; i++) {
//Add all our found terms to the final query
ScorePair pair = byScore.get(i);
bq.add(new TermQuery(new Term(pair.field,pair.term)),BooleanClause.Occur.SHOULD);
}
}
//Say, we want to score based on tf/idf
void putTermInMap(String field, String term, int freq, Map<String,ScorePair> map) {
String key = field + ":" + term;
if (map.containsKey(key))
map.get(key).increment();
else
map.put(key,new ScorePair(freq,field,term));
}
private class ScorePair implements Comparable{
int count = 0;
double idf;
String field;
String term;
ScorePair(int docfreq, String field, String term) {
count++;
//Standard Lucene idf calculation. This is calculated once per field:term
idf = (1 + Math.log(indexreader.numDocs()/((double)docfreq + 1)))^2;
this.field = field;
this.term = term;
}
void increment() { count++; }
double score() {
return Math.sqrt(count) * idf;
}
//Standard Lucene TF/IDF calculation, if I'm not mistaken about it.
int compareTo(ScorePair pair) {
if (this.score() < pair.score()) return -1;
else return 1;
}
}
(我并没有说这是功能代码,在它的当前状态)
谢谢你会尝试一下。 – j10
你能详细一点吗?你不愿意做什么? – javanna
是的,请定义“伪反馈” – phani
通过使用反馈我想扩大我的查询。我需要一些方法来扩展我的查询(反正应该没问题) – j10