1
我试图在MySQL中使用UNSIGNED INT来创建SUM()
。当我加入另一个表时,SIGNED INT成为UNSIGNED INT。当我做一个LEFT JOIN时,我的SIGNED INT被铸造成UNSIGNED
SELECT `weight` FROM `article_vote`
LEFT JOIN `vote` ON `vote`.`id` = `article_vote`.`article_id`
回报:
1
1
1
1
1
1
1
1
1
1
1
然而,SELECT weight FROM vote
回报:
1
1
1
1
-1
1
1
-1
-1
-1
1
任何想法?
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编辑
那些11行是在表中的总记录,所以不会有任何命令或限制。
编辑
表CREATE:
CREATE TABLE `vote` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_id` int(11) DEFAULT NULL,
`weight` int(11) NOT NULL,
`resource_type` varchar(255) NOT NULL,
`submited_date` datetime NOT NULL,
PRIMARY KEY (`id`),
KEY `IDX_5A108564A76ED395` (`user_id`),
CONSTRAINT `vote_ibfk_1` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=12 DEFAULT CHARSET=utf8;
CREATE TABLE `article_vote` (
`id` int(11) NOT NULL,
`article_id` int(11) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `IDX_8F6C754A62922701` (`anecdote_id`),
CONSTRAINT `article_vote_ibfk_1` FOREIGN KEY (`article_id`) REFERENCES `article` (`id`),
CONSTRAINT `article_vote_ibfk_2` FOREIGN KEY (`id`) REFERENCES `vote` (`id`) ON DELETE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
你能告诉我们这些2个查询的结果:'SELECT count(weight)FROM vote'和'SELECT count(weight)FROM article_vote LEFT JOIN vote.id = article_vote.article_id'? – gaRex
两者都返回11,其中我的表中的记录总数,我知道你要来的地方:)但这是完整的数据。 – JohnT
这两个表的结构是什么? –