如何从采购源代码中返回源代码？

Question

考虑foo.sh：

#!/bin/bash 
function foo() { 
    source another.sh 
    echo "This shouldn't be executed. Return code: $?" 
    return 0 
} 

foo 
echo "Return code: $?" 

然后another.sh：

echo "Inside another.sh" 
return 1 

运行./foo.sh打印：

Inside another.sh 
This shouldn't be executed. Return code: 1 
Return code: 0 

是否有替代方法包括一个源文件到另一个这样的return命令将从封装包含命令的函数返回而不是从命令本身返回？

Answer 1

一种选择是传播返回代码在foo.sh：

source another.sh || return $? 

然后：

$ ./foo.sh 
Inside another.sh 
Return code: 1 

另外，从整个脚本在another.sh 退出：

exit 1 

然后：

$ ./foo.sh 
Inside another.sh 
$ echo $? 
1