2013-07-17 22 views
0

我正在使用ListBox控件来显示项目,当我加倍Cilck项目意味着他们特定的项目字段将显示在xamgrid和问题是当我选择的项目意味着它的显示,但我需要显示在电网多事情一个或多个项目如何在XamGrid中显示多行

我的编码是,

private void LsImageGallery_MouseDoubleClick(object sender, MouseButtonEventArgs e) 
     { 
      RTBSPROJECT.DB.RTBSInventoryMgmtEntities2 MyRTBSinventoryDB = new DB.RTBSInventoryMgmtEntities2(); 

      RTBSPROJECT.DB.RTBSInventoryMgmtEntities2 DB_Linq = new DB.RTBSInventoryMgmtEntities2(); 
     try 
     { 

     string curItem = LsImageGallery.SelectedItem.ToString(); 

     #region 

     if (cmbItemCombo.SelectedItem == null) 
     { 


      var SelectedImage = (ImageEntity)this.LsImageGallery.SelectedItem; 

      string ItemName = SelectedImage.ItemName_EN; 

      var query = (from MyItems in MyRTBSinventoryDB.tbl_ItemMaster 
         where MyItems.ActiveFlag == true && 
         MyItems.ItemName_EN == ItemName 
         select MyItems).ToList(); 

      xamGrid1.ItemsSource = query; 
} 

每一次它显示一个记录,如果我选择的第二指前面的选择不应该清除这两个应该显示请帮我..

+0

请有人回复 – user2568244

回答

0

我是不是100%确定你在这里问的是什么,但我会继续努力。它看起来像你试图添加更多的行到DataGrid,但只有新的项目正在显示。

这是因为您正在更改DataGrid的ItemsSource属性,如果您希望将新项目添加到底部,那么ItemsSource需要保持不变,并添加新行。

这可以使用DataGrid上的Items.Add()方法完成,循环遍历数据行并为每个数据行调用add,或者您可以创建一个只需双击就添加的项目集合,I在这里提供了第二个例子。

像你的应用程序一样,它显示一个ListBox和一个DataGrid,每次你双击列表框中的一个项目时,会有更多的行被添加到DataGrid中。

XAML

<Window x:Class="WpfApplication1.MainWindow" 
      xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" 
      xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" 
      DataContext="{Binding RelativeSource={RelativeSource Self}}" 
      Title="MainWindow" Height="350" Width="525"> 
     <Grid> 
      <Grid.ColumnDefinitions> 
       <ColumnDefinition/> 
       <ColumnDefinition/> 
      </Grid.ColumnDefinitions> 
      <ListBox Grid.Column="0" ItemsSource="{Binding Items}" MouseDoubleClick="ListBox_MouseDoubleClick"/> 
      <DataGrid Grid.Column="1" ItemsSource="{Binding GridItems}"> 
       <DataGrid.Columns> 
        <DataGridTextColumn Binding="{Binding}"/> 
       </DataGrid.Columns> 
      </DataGrid> 
     </Grid> 
    </Window> 

代码背后

using System; 
using System.Collections.ObjectModel; 
using System.Windows; 
using System.Windows.Input; 

namespace WpfApplication1 
{ 
    public partial class MainWindow : Window 
    { 
     // This collection is bound to the ListBox so there are items to select from. 
     public ObservableCollection<object> Items 
     { 
      get { return (ObservableCollection<object>)GetValue(ItemsProperty); } 
      set { SetValue(ItemsProperty, value); } 
     } 
     public static readonly DependencyProperty ItemsProperty = 
      DependencyProperty.Register("Items", typeof(ObservableCollection<object>), typeof(MainWindow), new PropertyMetadata(null)); 

     // On double click of each item in the ListBox more items will be added to this collection. 
     public ObservableCollection<object> GridItems 
     { 
      get { return (ObservableCollection<object>)GetValue(GridItemsProperty); } 
      set { SetValue(GridItemsProperty, value); } 
     }  
     public static readonly DependencyProperty GridItemsProperty = 
      DependencyProperty.Register("GridItems", typeof(ObservableCollection<object>), typeof(MainWindow), new PropertyMetadata(null)); 

     public MainWindow() 
     { 
      InitializeComponent(); 

      // Some demo items so we can double click. 
      Items = new ObservableCollection<object>(); 
      Items.Add("test item 1"); 
      Items.Add("test item 2"); 
      Items.Add("test item 3"); 
      Items.Add("test item 4"); 
      Items.Add("test item 5"); 
      Items.Add("test item 6"); 
      Items.Add("test item 7"); 

      GridItems = new ObservableCollection<object>(); 
     } 

     private void ListBox_MouseDoubleClick(object sender, MouseButtonEventArgs e) 
     { 
      // These would be the entries from your database, I'm going to add random numbers. 
      Random rnd = new Random(); 

      for (int i = 0; i < rnd.Next(5); i++) 
       GridItems.Add(rnd.Next(100)); 
     } 
    } 
}