0
count = 10, 100, 1000, 10000
难度使用timeit模块
为计的每一个值,我需要使用timeit执行该方法5次,并打印出min值和实际的5个值。
numstring包含四个函数。
输出应该像(共16行):
numbers_string1,计数= 10,最小= 0.0001,实际值= [0.0001,0.0002,0.0001,...]
numbers_string1 ,计数= 100,最小值= 0.002,实际值= [0.002,0.002,0.003,...]
....
numbers_string4,计数= 10000,分= 0.1的实际值= [.... ]
为此,我试过这样:
我的代码:
from numstring import *
import timeit
def profile_timeit():
funcs_list = [numbers_string1, numbers_string2, numbers_string3, num_strings4]
for i in funcs_list:
for count in [10, 100, 1000, 10000]:
actuals = timeit.timeit(stmt='i(count)', number=4, setup='from __main__ import *')
print "{0} count = {1} \t min = {2} \t actuals = {3}".format(i, count, min(actuals), actuals)
print "\n"
if __name__ == "__main__":
profile_timeit()
任何人可以请帮助我。在此先感谢
是的,你是绝对正确的..谢谢 – coderusher
你好阿卜杜拉你能解释我如何做项目? – user3397770