获取错误mysqli_result类的对象无法转换为字符串

我得到一个错误，并为我的生活无法弄清楚。我的代码是那种凌乱使手表：获取错误mysqli_result类的对象无法转换为字符串

$hostname = ""; //SET SERVER/HOSTNAME 
$dbusername = ""; //SET DATABASE USERNAME 
$dbname = ""; //SET DATABASE NAME 
$dbpassword = ""; //SET DATABASE USERNAME 
$link = mysqli_connect($hostname, $dbusername, $dbpassword, $dbname); 
if (!$link) { 
die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error()); 
} 

$sql = "SELECT * FROM utility WHERE `program_code` = '$program_code'"; 
$result = mysqli_query($link, $sql, MYSQLI_USE_RESULT); 
if (!$result) 
{ 
    echo 'Error: ', $mysqli->error; 
} 



while($row = $result->fetch_assoc()){ 
    $program_code1 = $row['program_code']; 
    $utility_company = $row['utility_company']; 
    $rate = $row['rate']; 
    $term = $row['term']; 
} 

$sql1 = "INSERT INTO v88374 (id, ldc_account_num, revenue_class_desc, first_name, last_name, home_phone_num, sline1_addr, scity_name, spostal_code, marketer_name, distributor_name, service_type_desc, bill_method, enroll_type_desc, requested_start_date, plan_desc, contract_start_date, contract_end_date, fixed_commodity_amt, vendor_id, office_id, agent_id, customer_name, contact_name, result, promo_code, validation_code, email, state, bname, baddress, program_code, date) VALUES ('','$ldc_account_num1','$revenue_class_desc','$first_name1','$last_name1', '$home_phone_num1','$sline1_addr1','$scity_name1','$spostal_code1','','$utility_company','$service_type_desc','$bill_method','$enroll_type_desc','$requested_start_date','$plan_desc','$contract_start_date','$contract_end_date','$rate','$vendor_id','$office_id','$agent_id1','$customer_name','$contact_name','$result','$promo_code','$validation_code1','$email1','$state1','$bname1','$baddress1','$program_code1', now())"; 
$result1 = mysqli_query($link, $sql1, MYSQLI_STORE_RESULT); 
if (!$result1) 
{ 
echo 'Error: ', $mysqli->error; 
} 
else if ($result1){ 

     echo "Thank you. Information submitted."; 

}

我的第二个SQL语句开始时我正在错误（在这个问题上的主题），在SQL1 $ = long_string_of_code 我想这件事情与我的变量可能来自第一条语句吗？如果我回应我的变量从第一个状态，我得到他们一切OK。所以我不确定交易是什么。任何帮助表示赞赏，我知道这是很多代码要通过。谢谢。

来源

2013-08-02 dkeeper09

如果将myslqi_query（）中的MYSQLI_USE_RESULT的第一个用法更改为MYSQLI_STORE_RESULT，会发生什么情况？ – CXJ

contact_name','$result','$promo_code'

您在第二个SQL中使用结果。它的一个对象，所以你不能用它作为一个字符串。更改该变量，它应该工作

来源

2013-08-02 22:49:19 exussum

你是救世主user1281385。我一直在看那件事一小时。谢谢。 – dkeeper09

获取错误mysqli_result类的对象无法转换为字符串

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