我得到一个错误的最后3如果else语句

if (annual <= lowincome && aChar == 'S') 
    owe = annual * .25; 
else if (annual > lowincome || annual < medincome && aChar == 'S') 
    owe = annual * .50; 
else if (annual > medincome && Char == 'S') 
    owe = annual * .75; 
else if (aChar == 'M' && annual <= lowincome) 
    owe = annual *.24; 
else if(annual > low income || annual < medincome && aChar == 'M') 
    owe = annual * .49; 
else if(annual > medincome && Char == 'M') 
    owe = annual * .74;

我希望用户输入，如果他们是已婚还是单身然后去虽然计算发现那里每年income.I后得到这个错误我得到一个错误的最后3如果else语句

TaxReturn.java:54: error: ')' expect 
if(annual > low income || annual < medincome && aChar == 'M') 
             ^
TaxReturn.java:54: error: not a statement 
if(annual > low income || annual < medincome && aChar == 'M') 
               ^
TaxReturn.java:54: error: ';' expect 
if(annual > low income || annual < medincome && aChar == 'M') 

TaxReturn.java:56: error: 'else' without 'if' 
else 
          ^
TaxReturn.java:68: error: class, interface, or enum expected 
}  
^ 
5 errors

来源

2013-01-07 user1925540

[标签：家庭作业]？ **这个标签是OBSOLETE **。 –

为什么你不喜欢大括号？无论如何，这是你的完整代码吗？ –

OMG太多if-else-if-else .. !!你的代码中存在错误，我建议你逐个剖析，你将会知道你在哪里做过错误:) –

if(annual > low income || annual < medincome && aChar == 'M')

应该

if(annual > lowincome || annual < medincome && aChar == 'M')

无论low也不income被认定为十进制拉雷变量。

来源

2013-01-07 14:50:07

您应该使用括号给你的条件完全意义...

if (annual > low income ||( annual < medincome && aChar == 'M')) ...

来源

2013-01-07 14:53:34

你应该做这个，返回欠量一个辅助方法，这将让你摆脱那个讨厌的嵌套业务。如果嵌套了三个以上的if语句，则需要重新考虑如何解决问题。我向你保证，你会因此而失去积分。

有人说，由于“低”和“收入”之间的空间，你的代码被轰炸......应该是“低收入”。

这里有一个如何考虑重新安排你的代码的例子...

public BigDecimal getOwed(BigDecimal annual){ 
    if (annual <= lowincome && aChar == 'S'){ 
     return owe = annual * .25; 
    } 

    if (annual > lowincome || annual < medincome && aChar == 'S'){ 
      return owe = annual * .50; 
    } 

    if (annual > medincome && Char == 'S'){ 
     return owe = annual * .75; 
    } 
    /*go through all your cases in this fashion 
    . 
    . 
    . 
    handle the case that it doesnt match any (should never occur). 
    */ 

}

这种方式是更清洁和更容易阅读。

来源

2013-01-07 15:15:40 djjolicoeur

这个来自您的错误跟踪

if(annual > low income || annual < medincome && aChar == 'M')

你不能有空间内可变的，就像你low income

来源

2013-01-07 16:25:55 user902383

不应把该代码：

if (annual > medincome && Char == 'S'){ 
    return owe = annual * .75; 
}

是这样的：

if (annual > medincome && aChar == 'S'){ 
    return owe = annual * .75; 
}

它看起来像你不一致评估你的变量aChar。你也可以在最后的“else if”语句中执行此操作。

来源

2013-01-07 16:38:34

我得到一个错误的最后3如果else语句

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