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const int pingPin = 7;
const int ledPin = 11;
const int ledPin2 = 10;
int ledLevel = 0;
int ledLevel2 = 255;
int constraint = 0;
void setup()
{
pinMode(ledPin, OUTPUT);
Serial.begin(9600);
}
void loop()
{
long duration, inches, cm;
pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(5);
pinMode(pingPin, INPUT);
duration = pulseIn(pingPin, HIGH);
constraint = constrain(duration, 500, 8000);
ledLevel = map(constraint, 500, 8000, 255, 0);
if (ledLevel < 192) {
analogWrite(ledPin, ledLevel);
ledLevel2 = ledLevel2 - 255;
} else if (ledlevel >= 192) {
analogWrite(ledPin, ledLevel);
analogWrite(ledPin2, ledLevel2);
}
Serial.println(duration);
delay(100);
}
这是我的arduino代码,当有人开始走向超声波传感器时,它会打开一个led,当他们获得3/4的方式打开第二个led时。当我尝试编译它时出现“'ledLevel'未在此范围内声明”,并突出显示else if语句。arduino else if语句错误
哦,我的天哪!我觉得很愚蠢!非常感谢。 – Michaelslec
适合所有人,大声笑。请注册并标记为答案。 –