2012-12-10 157 views
0
const int pingPin = 7; 
const int ledPin = 11; 
const int ledPin2 = 10; 
int ledLevel = 0; 
int ledLevel2 = 255; 
int constraint = 0; 

void setup() 
{ 
    pinMode(ledPin, OUTPUT); 
    Serial.begin(9600); 
} 

void loop() 
{ 
    long duration, inches, cm; 

    pinMode(pingPin, OUTPUT); 
    digitalWrite(pingPin, LOW); 
    delayMicroseconds(2); 
    digitalWrite(pingPin, HIGH); 
    delayMicroseconds(5); 

    pinMode(pingPin, INPUT); 
    duration = pulseIn(pingPin, HIGH); 
    constraint = constrain(duration, 500, 8000); 

    ledLevel = map(constraint, 500, 8000, 255, 0); 

    if (ledLevel < 192) { 
    analogWrite(ledPin, ledLevel); 
    ledLevel2 = ledLevel2 - 255; 
    } else if (ledlevel >= 192) { 
    analogWrite(ledPin, ledLevel); 
    analogWrite(ledPin2, ledLevel2); 
    } 

    Serial.println(duration); 
    delay(100); 
} 

这是我的arduino代码,当有人开始走向超声波传感器时,它会打开一个led,当他们获得3/4的方式打开第二个led时。当我尝试编译它时出现“'ledLevel'未在此范围内声明”,并突出显示else if语句。arduino else if语句错误

回答

5
else if (ledlevel >= 192) 

ledLevel而不是ledlevel(L是大写)
应该

else if (ledLevel >= 192) 
+0

哦,我的天哪!我觉得很愚蠢!非常感谢。 – Michaelslec

+0

适合所有人,大声笑。请注册并标记为答案。 –