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我想写一个断言,只有当一个信号在'clk'的上升沿转换时才会触发。我写了下面的代码来测试我的想法Systemverilog assertion来检查坏信号转换
module test();
bit clk, clkb;
int d;
assign clkb = ~clk;
initial begin
clk = 0;
forever #100 clk = ~clk;
end
initial begin
d = 10;
#150 d = 20;
end
sva_d_chgd: assert property (@(posedge clk) $stable(d,@(clkb)))
else $error($psprintf("err: time = %0d, clk = %b, d = %0d", $time, clk, d));
always @ (d or clk) begin
$display("time = %0d, clk = %b, d = %0d", $time, clk, d);
if ($time > 200) $finish;
end
endmodule
上面的代码返回VCS以下的输出:
time = 0, clk = 0, d = 10
time = 100, clk = 1, d = 10
"test.vs", 18: test.sva_d_chgd: started at 100s failed at 100s
Offending '$stable(d, @(clkb))'
Error: "test.vs", 18: test.sva_d_chgd: at time 100
err: time = 100, clk = 1, d = 10
time = 150, clk = 1, d = 20
time = 200, clk = 0, d = 20
time = 300, clk = 1, d = 20
$finish called from file "test.vs", line 23.
$finish at simulation time 300
为什么在时间100断言火的时候“d”保持稳定,直到时间150?
感谢您指出重置问题,但为什么断言仍不正确?在300时刻,d仍然是20的值,那为什么断言是火呢? – user2400361
你正在评估你在每个posedge clk的主张。在300ns(posedge clk),“d”在250ns变化,这在clkb的200ns和300ns边缘之间,所以你的断言被评估为假。合理? – Ciano
是的,它的确如此。我误解了稳定的工作 – user2400361