2013-02-02 33 views
2

的我使用11克Express版本,Eclipse的朱诺,Java 6的持久性,Oracle瘦,ORA-12505,TNS监听器目前不知道SID

甲骨文启动并运行甚至试图立即停机和启动,但没有得到SID听者错误

<?xml version="1.0" encoding="UTF-8"?> 
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"> 

    <persistence-unit name="default" transaction-type="RESOURCE_LOCAL"> 
    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider> 
    <class>com.crspdemo.Employee</class> 
    <properties> 
     <property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@localhost:1521:jsfDatabase"/> 
     <property name="javax.persistence.jdbc.password" value="admin"/> 
     <property name="javax.persistence.jdbc.driver" value="oracle.jdbc.driver.OracleDriver"/> 
     <property name="javax.persistence.jdbc.user" value="system"/> 
     <!--<property name="eclipselink.ddl-generation" value="create-tables"/>--> 
    </properties> 
    </persistence-unit> 

</persistence> 

错误:

Caused by: javax.persistence.PersistenceException: Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.2.0.v20110202-r8913): org.eclipse.persistence.exceptions.DatabaseException 

内部异常:java.sql.SQLException中:监听拒绝合作并出现以下错误nnection: ORA-12505,TNS:监听器目前不知道SID的连接描述符中给出

LISTNER.ORA

listner.ora

回答

2

尝试使用默认SID为XE :

<property name="javax.persistence.jdbc.url" value="jdbc:oracle:thin:@localhost:1521:XE"/> 
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