2012-12-18 53 views
0

我正在尝试编写一个简单的PL/SQL过程,但我不断收到错误,我不明白。有一些 语法失败,如果有人能帮助我,我将不胜感激。 我需要创建一个程序,允许我插入一个特定的人(varchar2)与两个日期(日期),他的合同期限。然而,他的合同不能在现有日期之间,因此不能重叠,同一个人可以有多个联系人,但只能在完全不同的时间段之间。 我知道我需要使用INTERSECT,这只是我很困惑如何在这里使用它,因为我只有一个表。我之前有两张桌子相交,我怎么在这里相交呢?我;米也不知道我是否可以有2如果发言 谢谢!创建正确的过程

CREATE OR REPLACE PROCEDURE test1 
(name    VARCHAR2, 
startDate  DATE, 
endDate   DATE) 
AS 
overlap  NUMBER := 0; 
CURSOR cursor IS 
SELECT date_from, date_to FROM contractTable; 
BEGIN 
    FOR row IN cursor LOOP 
    /*check if there is an overlap between dates*/ 
    IF (startDate, endDate) INTERESECT (SELECT date_from, date_to FROM ContractTable) THEN 
    overlap := overlap + 1;  
    END IF; 
    /*if there isn't, then insert new contact for this person*/ 
    IF overlap <= 0 THEN 
    INSERT INTO ContractTable VALUES(name, startDate, endDate); 
    END IF; 
    END test1; 

回答

0
CREATE PROCEDURE test1 (l_name IN VARCHAR2, l_start_date IN DATE, l_end_date IN DATE) 
IS 

    l_overlap_check NUMBER; 

BEGIN 

    SELECT count(*) INTO l_overlap_check 
     FROM contract 
    WHERE (l_start_date between start_date and end_date 
      OR 
      l_end_date between start_date and end_date) 
     AND l_name = name; 

    IF l_overlap_check = 0 THEN 
     INSERT INTO contract (name, start_date, end_date) 
         VALUES (l_name, l_start, l_end); 
    END IF; 

END; 

我没有Oracle环境中方便,但应该是你所需要的。

+0

我会在程序中包含一个异常处理程序作为“最佳实践”。 – tale852150