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我试图创建一个使用rapidjson的JSON,我遇到了一些意想不到的问题,无法生成正确的输出。rapidjson正确的JSON创建
我创建和填充像这样的文件:
Document d;
d.SetObject();
rapidjson::Document::AllocatorType& allocator = d.GetAllocator();
size_t sz = allocator.Size();
d.AddMember("version", 1, allocator);
d.AddMember("testId", 2, allocator);
d.AddMember("group", 3, allocator);
d.AddMember("order", 4, allocator);
Value tests(kArrayType);
Value obj(kObjectType);
Value val(kObjectType);
obj.AddMember("id", 1, allocator);
string description = "a description";
val.SetString(description.c_str(), static_cast<SizeType>(description.length()), allocator);
obj.AddMember("description", val, allocator);
string help = "some help";
val.SetString(help.c_str(), static_cast<SizeType>(help.length()), allocator);
obj.AddMember("help", val, allocator);
string workgroup = "a workgroup";
val.SetString(workgroup.c_str(), static_cast<SizeType>(workgroup.length()), allocator);
obj.AddMember("workgroup", val, allocator);
val.SetBool(true);
obj.AddMember("online", val, allocator);
tests.PushBack(obj, allocator);
d.AddMember("tests", tests, allocator);
// Convert JSON document to string
rapidjson::StringBuffer strbuf;
rapidjson::PrettyWriter<rapidjson::StringBuffer> writer(strbuf);
d.Accept(writer);
当我运行这段代码,我期待获得此JSON:
{
"version": 1,
"testId": 2,
"group": 3,
"order": 4,
"tests": [
{
"id": 1,
"description": "a description",
"help": "some help",
"workgroup": "a workgroup",
"online": true
}
]
}
但实际产生的输出...
{
"version": 1,
"testId": 2,
"group": 3,
"order": 4,
"tests": [
{
"id": 1,
"description": "a description",
"help": "some help",
"workgroup": "a workgroup",
"online": tr{
"version": 1,
"testId": 2,
"group": 3,
"order": 4,
"tests": [
{
"id": 1,
"description": "a description",
"help": "some help",
"workgroup": "a workgroup",
"online": true
}
]
}
任何想法?
你是否必须这样做''allocator''魔术?还是有重载,你可以在没有它们的情况下构建DOM?我的直觉告诉我,这看起来有点偏离。 – BitTickler
除此之外,您多次重复使用相同的''val''实例。也许这是一个非使用案例。 – BitTickler
从我可以告诉我,我只能从SetString调用中删除分配器,并没有任何效果。关于重复使用val,我已经尝试过不重用它,结果也是一样的。 –