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我试图用/在低于给定的数据一起提取字母之间的数据(我不想在多年的“s”和 - )。正则表达式提取标签
football soccer/basketball
1990s-1999s
我在preg_match_all
函数中使用/\D[a-zA-Z].*/s
。它返回字母和数字(当在rubular.com中进行测试时,上述表达式可以工作,但在PHP程序中不会)。
我试图用/在低于给定的数据一起提取字母之间的数据(我不想在多年的“s”和 - )。正则表达式提取标签
football soccer/basketball
1990s-1999s
我在preg_match_all
函数中使用/\D[a-zA-Z].*/s
。它返回字母和数字(当在rubular.com中进行测试时,上述表达式可以工作,但在PHP程序中不会)。
# ^([\D]+)$
#
# Options: case insensitive;^and $ match at line breaks
#
# Assert position at the beginning of a line (at beginning of the string or after a line break character) «^»
# Match the regular expression below and capture its match into backreference number 1 «([\D]+)»
# Match a single character that is not a digit 0..9 «[\D]+»
# Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
# Assert position at the end of a line (at the end of the string or before a line break character) «$»
preg_match_all('/^([\D]+)$/im', $subject, $result, PREG_PATTERN_ORDER);
$result = $result[0];
谢谢。我试过了,它的工作原理 – 2013-03-14 06:05:56
@PritamRao很高兴我能帮到你。请检查它作为接受的答案:) – 2013-03-14 08:45:57