错误：格式％d期望类型为int，但参数2的类型为double（*）（int，int）

Question

我似乎无法在我的printf语句中找出这个错误。每当我将整数格式说明符浮动，反之亦然，我只是得到同样的错误。

 error: format â%fâ expects type âdoubleâ, but argument 2 has type âdouble (*)(int,  int)â 

这里是我的代码

void outputScores(int x, int y) 
{ 
if(((x&y)>=1) && ((x&y)<=20)) 
{ 
printf("------------------------------\n"); 
printf("\n"); 
printf("Field: %d,%d\n",x,y); 
printf("\n"); 
printf("Soil quality: %f\n",soilQuality); 
printf("Sun exposure: %d\n",sunExposure); 
printf("Irrigation exposure: %d\n",irrigationExposure); 
printf("\n"); 
printf("Estimated yield: %d\n",estimatedYield); 
printf("Estimated quality: %d\n",estimatedQuality); 
printf("Time to harvest: %d\n",harvestTime); 
printf("\n"); 
printf("Overall Score: %f\n",fieldScore); 
printf("\n"); 
printf("------------------------------\n"); 
} 
else 
{ 
printf("Field %d, %d is invalid!\n",x,y); 
} 
return; 
} 

一部分，这里是功能

double soilQuality(int x, int y) 
{ 
if((x>=1) && (x<=20) && (y>=1) && (y<=20)) 
{ 
if((x+y)%2==1) 
{ 
int soilQuality=(1+(sqrt((x-10)*(x-10))+((y-10)*(y-10)))); 
return soilQuality; 
} 
else 
{ 
int soilQuality=(1+((abs(x-10)+abs(y-10))/2)); 
return soilQuality; 
} 
} 
else 
{ 
return -1; 
} 
} 

Answer 1

在printf()，%f期待double，但你给它一个指向函数类型double (*)(int, int)。

因此改变

printf("Soil quality: %f\n",soilQuality); 

到

printf("Soil quality: %f\n",soilQuality(x, y)); 

，然后再试一次。