0
我是Visual Studio中的新成员。我使用SpecFlow使用Visual Studio 2015。下面是功能文件:生成不正确方法的SpecFlow步骤生成方案
@mytag
Scenario Outline: Successful Authentication
Given I am a user of type <user>
When I hit the application URL
And I provide <email>
And I click on Log In Button
Then I will be landed to the Home Page
And I will be able to see <name> on the Home Page
Examples:
| user | email | name |
| admin | [email protected] | alpha |
| non-admin | [email protected] | beta |
当我生成步骤的定义,我来代替变量的预期参数,而不是产生如下图所示的方法:
[Given(@"I am a user of type admin")]
public void GivenIAmAUserOfTypeAdmin()
{
ScenarioContext.Current.Pending();
}
我,而不是期待方法如:
[Given(@"I am a user of type '(.*)'")]
public void GivenIAmAUserOfType(string p0)
{
ScenarioContext.Current.Pending();
}
我错过了什么?
谢谢丹尼尔。是的,它解决了这个问题。 –