MSSQL - 返回选择

Question

我想编写一个需要2个参数的过程（Int，string）如果表中有一行存在，我会得到@dane = 1;最后我想选择@dane，但我的程序不好。我不能使用return @dane。

USE [SS] 
    GO 

    SET ANSI_NULLS ON 
    GO 
    SET QUOTED_IDENTIFIER ON 
    GO 

    CREATE PROCEDURE [permission].[CheckSkill] 
(
    @SkillId INT, -- Identyfikator użytkownika 
    @Description NVARCHAR(100) = NULL 
) 
AS 
BEGIN 
    SET NOCOUNT ON; 
    DECLARE @dana as int 
    SET @dana = 0 

    -- this is redundant: 
    --SET @Description = RTRIM(LTRIM(ISNULL(@Description,''))) 

    IF EXISTS (SELECT * FROM permission.UserXSkill Where permission.UserXSkill.SkillId = @SkillId) 
    BEGIN 
     SET @dana = 1; 
    END 

    SELECT @dana AS ID; 
END 
GO 

主题[关闭]感谢您的帮助。

Answer 1

将值分配给变量时，需要使用SET或SELECT。

EXISTS似乎有助于需求在IF块

的@Description参数没有用，多余的

USE [SS] 
GO 

SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 

CREATE PROCEDURE [permission].[CheckSkill] 
(
    @SkillId INT, -- Identyfikator użytkownika 
    @Description NVARCHAR(100) = NULL, 

) 
AS 
BEGIN 
    SET NOCOUNT ON; 
    DECLARE @dana as int 
    SET @dana = 0 

    -- this is redundant: 
    --SET @Description = RTRIM(LTRIM(ISNULL(@Description,''))) 

    IF EXISTS (SELECT * FROM permission.UserXSkill Where permission.UserXSkill = @SkillId) 
    BEGIN 
     SET @dana = 1; 
    END 

    SELECT @dana AS ID; 
END 
GO