程序中没有输出？

Question

我正在制作一个程序来洗牌一套牌，并发出两只手，但现在，没有输出！我梳理了无限循环的代码，但我找不到任何东西！有人可以帮帮我吗？

// (Description in Word File) 
#include <iostream> 
#include <cstdlib> 
#include <ctime> 
#include <string> 
using namespace std; 

unsigned seed = time(0); // for use of rand() 

const int SUIT = 4; 
const int FACE = 13; 
const int HAND = 5; 

// A couple of reference arrays. 
const string SUITS[SUIT] = {" Hearts", " Diamonds", " Clubs", " Spades"}; 
const string FACES[FACE] = {"Ace of", "Two of", "Three of", 
          "Four of", "Five of", "Six of", "Seven of", 
          "Eight of", "Nine of", "Ten of", 
          "Jack of", "Queen of", "King of"}; 

// The reason that these functions are in Main is because 
// it gives me error 2065: undeclared identifier otherwise. 
void shuffle(string[][FACE]); 
void deal(string[][FACE], string[HAND]); 
void displayDeck(string[][FACE]); 
void displayHand(string[HAND]); 

int main() 
{ 
    string deck[SUIT][FACE]; 
    string hand1[HAND]; 
    string hand2[HAND]; 

    srand(seed); // for use of rand() 

    // Shuffle the deck. 
    shuffle(deck); 

     // Now display the deck 
    displayDeck(deck); 

    // Deal for each hand. 
    deal(deck, hand1); 
    deal(deck, hand2); 

    // Now display each hand. 
    displayHand(hand1); 
    displayHand(hand2); 

    return 0; 
} 

// This function will keep track of face values 
// for the shuffle function 
bool duplCheck(string cards[][FACE], int suit, int face) 
{ 
    bool status = true; 
    for (int count1 = 0; count1 != SUIT; count1++) 
     for (int count2 = 0; count2 != FACE; count2++) 
      if (cards[count1][count2] == cards[suit][face] 
       && suit != count1 && face != count2) 
       return false; 
    return status; 
} 

// This function will shuffle the deck. 
void shuffle(string cards[][FACE]) 
{ 
    int randFace, randSuit; 
    // These loops will assign random face values 
    // and suits to each place in cards[][]. 
    for (int count1 = 0; count1 != SUIT; count1++) 
     for (int count2 = 0; count2 != FACE; count2++) 
     { 
      do 
      { 
       randFace = rand() % FACE; 
       randSuit = rand() % SUIT; 
       if (duplCheck(cards, randSuit, randFace) == true) 
        cards[count1][count2] = 
         FACES[randFace] + SUITS[randSuit]; 
      } while(duplCheck(cards, randSuit, randFace) == false); 
     } 
} 

// This function deals out a hand of five random cards. 
void deal(string cards[][FACE], string hand[HAND]) 
{ 
    for (int count = 0; count != HAND; count++) 
    { 
     // make random suit and face numbers 
     int randSuit = rand() % SUIT; 
     int randFace = rand() % FACE; 

     // If random card is not obsolete... 
     if (cards[randSuit][randFace] != "null") 
      // ...assign that card to hand. 
      hand[count] = cards[randSuit][randFace]; 

     // obsolete that card 
     cards[randSuit][randFace] = "null"; 
    } 
} 

void displayDeck(string cards[][FACE]) 
{ 
    std::cout << "\t\tThe Deck:\n\n"; 
    for (int count1 = 0; count1 != SUIT; count1++) 
     for (int count2 = 0; count2 != FACE; count2++) 
     { 
      std::cout << ((count1 * FACE) + count2 + 1) << " " 
       << cards[count1][count2] << endl; 
     } 
} 

void displayHand(string hand[HAND]) 
{ 

} 

Answer 1

你的问题是在洗牌，特别是在使用duplCheck。

void shuffle(string cards[][FACE]) 
{ 
    int randFace, randSuit; 
    // These loops will assign random face values 
    // and suits to each place in cards[][]. 
    for (int count1 = 0; count1 != SUIT; count1++) 
     for (int count2 = 0; count2 != FACE; count2++) 
     { 
      do 
      { 
       randFace = rand() % FACE; 
       randSuit = rand() % SUIT; 
       std::cout << count1 << "," << count2 << " trying " << randFace << "/" << randSuit << std::endl; 
       if (duplCheck(cards, randSuit, randFace) == true) { 
        std::cout << "duplCheck returned true" << std::endl; 
        cards[count1][count2] = 
         FACES[randFace] + SUITS[randSuit]; 
       } 
      } while(duplCheck(cards, randSuit, randFace) == false); 
     } 
} 

我添加了一些额外的输出。这演示了（http://ideone.com/BkZKD9）第一次运行duplCheck时不会返回false。

do 
{ 
    randFace = rand() % FACE; 
    randSuit = rand() % SUIT; 
    if (duplCheck(cards, randSuit, randFace) == true) { 
       ... this doesn't happen 
    } 
} while(duplCheck(cards, randSuit, randFace) == false); 

由于duplCheck返回false，您将永久保留在此循环中。

bool duplCheck(string cards[][FACE], int suit, int face) 
{ 
    bool status = true; 
    for (int count1 = 0; count1 != SUIT; count1++) 
     for (int count2 = 0; count2 != FACE; count2++) 
      if (cards[count1][count2] == cards[suit][face] 
       && suit != count1 && face != count2) 
       return false; 
    return status; 
} 

看来，duplCheck如果没有返回“假”，如果有重复和“真”，但你对它的使用预期相反：while循环停止时duplCheck返回true，预计如果有重复，duplCheck返回true。

Answer 2

您的显示手部功能为空。

void displayHand(string hand[HAND]) 
{ 
    cout << "Put some output here"; 
} 

Answer 3

问题是你的牌组最初是以空（“”）值开始的。您可以在开始调用shuffle（）之前填写此项，也可以将此检查添加到duplCheck（）的开头：

if(cards[suit][face].length() == 0) 
    return true;