智能代替重复的值蟒蛇

所以我有一个文件，我想通过走线并更换一些词是非常相似，实际上他们中的一些人的字符串：智能代替重复的值蟒蛇

uint8=("UINT8 ","PIN_UINT8 ") 
uint16=("UINT16 ","PIN_UINT16 ") 
uint32=("UINT32 ","PIN_UINT32 ") 
uint64=("UINT64 ","PIN_UINT64 ") 
int8=("INT8 ","PIN_INT32 ") 
int16=("INT16 ","PIN_INT16 ") 
int32=("INT32 ","PIN_INT32 ") 
int64=("INT64 ","PIN_INT64 ")

这些都是替代品。但我需要小心，因为INT8它的子串UINT8所以即使我有一场比赛，我需要检查它是否是UINT8或INT8。

我写了一些代码，但远没有工作。

while pos!=-1: 
           print line[pos:] 
           if "INT8 " in line[pos:]: 
            pos=line.find("INT8",pos_final) 
            if "U" == line[pos-1]: 
             line = line.rstrip().replace(*uint8) 
            else: 
             print line[pos-1] 
             line = line.rstrip().replace(*int8) 
            pos+=5 #len(PIN_)+1 
           elif "INT16 " in line[pos:]: 
            pos=line.find("INT16",pos_final) 
            if "U" == line[pos-1]: 
             line = line.rstrip().replace(*uint16) 
            else: 
             print line[pos-1] 
             line = line.rstrip().replace(*int16) 
            pos+=5      
           elif "INT32 " in line[pos:]: 
            pos=line.find("INT32",pos_final) 
            if "U" == line[pos-1]: 
             line = line.rstrip().replace(*uint32) 
            else: 
             print line[pos-1] 
             line = line.rstrip().replace(*int32) 
            pos+=5      
           elif "INT64 " in line[pos:]: 
            pos=line.find("INT64",pos_final) 
            if "U" == line[pos-1]: 
             line = line.rstrip().replace(*uint64) 
            else: 
             print line[pos-1] 
             line = line.rstrip().replace(*int64) 
            pos+=5 
           else: 
            pos =-1

在这里有该文件的某些行这样你就可以知道，如果反应是正确的，工作原理：

UINT32 CacheSize() const { return _cacheSize; } 
UINT32 LineSize() const { return _lineSize; } 
UINT32 Associativity(UINT64 obj, INT8 obj2) const { return _associativity; } 
VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, UINT32 & setIndex) const 
VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, UINT32 & setIndex, UINT32 & lineIndex) const 
{ 
    const UINT32 lineMask = _lineSize - 1;

来源

2016-01-22 user1618465

只是做了UINT-替代的INT-替换之前，它应该工作... – L3viathan

也许使用正则表达式 - 're'模块 – furas

@ L3viathan改变''INT8到''PIN_INT8它会改变'PIN_UINT8 '到'PIN_UPIN_INT8' – furas

我假定您的文件中没有INT7 s。

import re 
text = """UINT32 CacheSize() const { return _cacheSize; } 
    UINT32 LineSize() const { return _lineSize; } 
    UINT32 Associativity(UINT64 obj, INT8 obj2) const { return _associativity; } 
    VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, UINT32 & setIndex) const 
    VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, UINT32 & setIndex, UINT32 & lineIndex) const 
    { 
     const UINT32 lineMask = _lineSize - 1 INT8; 
""" 
for line in text.split("\n"): 
    print re.sub(r'(U?INT\d+?)',r'PIN_\1', line)

来源

2016-01-22 04:44:24 L3viathan

您可以重新使用模块做，试试下面的代码

import re 
text = """UINT32 CacheSize() const { return _cacheSize; } 
    UINT32 LineSize() const { return _lineSize; } 
    UINT32 Associativity(UINT64 obj, INT8 obj2) const { return _associativity; } 
    VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, UINT32 & setIndex) const 
    VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, UINT32 & setIndex, UINT32 & lineIndex) const 
    { 
     const UINT32 lineMask = _lineSize - 1 INT8; 
""" 

for line in text.split("\n"): 
    line = re.sub("UINT8 ","PIN_UINT8 ", line) 
    line = re.sub("UINT16 ","PIN_UINT16 ", line) 
    line = re.sub("UINT32 ","PIN_UINT32 ", line) 
    line = re.sub("UINT64 ","PIN_UINT64 ", line) 
    line = re.sub("[^UPIN_]INT8 ","PIN_INT32 ", line) 
    line = re.sub("[^UPIN_]INT16 ","PIN_INT16 ", line) 
    line = re.sub("[^UPIN_]INT32 ","PIN_INT32 ", line) 
    line = re.sub("[^UPIN_]INT64 ","PIN_INT64 ", line) 
    print "\t\t",line

输出

PIN_UINT32 CacheSize() const { return _cacheSize; } 
PIN_UINT32 LineSize() const { return _lineSize; } 
PIN_UINT32 Associativity(PIN_UINT64 obj,PIN_INT32 obj2) const { return _associativity; } 
VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, PIN_UINT32 & setIndex) const 
VOID SplitAddress(const ADDRINT addr, CACHE_TAG & tag, PIN_UINT32 & setIndex, PIN_UINT32 & lineIndex) const 
{ 
    const PIN_UINT32 lineMask = _lineSize - 1PIN_INT32 ;

来源

2016-01-22 04:40:47

智能代替重复的值蟒蛇

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