我得到这个JSON字符串:解析到时的JSONObject没有被正确创建(可以JSON格式错误?)
[
{
"id": 135,
"date": "2013-08-30 19:00:29",
"timestamp": "2013-08-30 19:00:29",
"lat": "54.328274",
"long": "-2.747215",
"strap": "annual International Festival of Street Arts",
"link": "http://dev.website.co.uk//?p=135",
"title": "Title"
}
]
这肯定是正确的JSON语法IM(在iOS应用正常工作),但是JSONObject它捕获错误。 Java:
public static JSONObject getJSONfromURL(String url){
//initialize
InputStream is = null;
String result = "";
JSONObject jArray = null;
//http post
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
} catch (Exception e) {
Log.e("log_tag", "Error converting result "+e.toString());
}
//try parse the string to a JSON object
try {
Log.d("log_tag", "jresult: " + result + "finish");
jArray = new JSONObject(result);
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data "+e.toString());
}
return jArray;
}
JSON中某处出现错误吗?
感谢
JSONArray
!这里最好的解释,谢谢!我会接受它,当它允许:) –@JoshBoothe欢迎您。你也可以有一个try块,并且有很多基于异常层次的catch块 – Raghunandan
@Raghunandan好解释 – Blackbelt