1
我有以下结构,并且您可以看到json中没有返回“methods”数据。为什么? 这是一个UML建模程序。Json_encode缺失数据
object(UClass)[1]
public 'classname' => string 'Class_Temp_1311967657' (length=21)
public 'classtype' => string 'public' (length=6)
public 'methods' =>
array
0 =>
object(UFunction)[2]
private 'name' => string 'Bill' (length=4)
private 'type' => null
private 'attributes' => null
private 'returntype' => null
1 =>
object(UFunction)[3]
private 'name' => string 'Function_Temp_1311967657' (length=24)
private 'type' => null
private 'attributes' => null
private 'returntype' => null
public 'attributes' =>
array
'person' =>
array
'type' => string 'string' (length=6)
'visability' => string 'public' (length=6)
'id' =>
array
'type' => string 'int' (length=3)
'visability' => string 'public' (length=6)
private 'interfacesUsed' =>
array
empty
并且json看起来像这样
{"classname":"Class_Temp_1311967657","classtype":"public","methods":[{},{}],"attributes":{"person":{"type":"string","visability":"public"},"id":{"type":"int","visability":"public"}}}
也许你可以创建一个公共方法“toJson()”,也可以序列化私有成员? –
啊。谢谢你错过了。 – mike628