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我正在用两个按钮写一个简单的草图。为了处理返回的事件数，我写了一个名为changeButtonStatus（作为一个参数，我通过一个按钮PIN）功能的按钮状态：几个按钮的一个处理函数
- 0 - 没有点击，
- 1 - 单一的点击，
- 2 - 双击，
- 3 - 长按，
- 4 - 长按后发布。
在主循环中，我为每个我的两个按钮调用此函数，并使用Serial.println()打印出消息。
问题是，我的素描只适用于一个按钮，并且它不适用于两个或更多按钮。
这里是我的代码：
#include <elapsedMillis.h>
int but1 = 3;
int but2 = 4;
int eventBut1, eventBut2;
int currentButtonStatus = 0; // 0 - button is not pressed
// 1 - button is pressed for the first time
// 2 - button is released after being pressed
// 3 - button is pressed for the second time
unsigned long currentButtonStatusStart1; // number of milliseconds when the status has changed to 1
unsigned long currentButtonStatusStart2; // number of milliseconds when the status has changed to 2
unsigned long currentButtonStatusStart3; // number of milliseconds when the status has changed to 3
const int delayFalse = 30; // if the value is less than 30 milliseconds, one press is not registered
const int delayLongSingleClick = 400; // if the value is greater than 400 milliseconds, long press is reegistered
const int delayDeltaDoubleClick = 300; // delay to registere double clck
void setup() {
pinMode (but1, INPUT);
pinMode (but2, INPUT);
Serial.begin(9600);
}
void loop() {
eventBut1 = changeButtonStatus(but1); // variable to keep the state of but1 (not pressed, single press, double press, long press)
eventBut2 = changeButtonStatus(but2); // variable to keep the state of but2 (not pressed, single press, double press, long press)
if (eventBut1 > 0) {
if (eventBut1 == 1) {Serial.println("But1 Single click");}
if (eventBut1 == 4) {Serial.println("But1 is released after long press");}
}
if (eventBut2 > 0) {
if (eventBut2 == 1) {Serial.println("But2 Single click");}
if (eventBut2 == 2) {Serial.println("But2 Double press");}
}
}
/**
* Change current button status
* @return = 0 - not pressed
* 1 - single click
* 2 - double click
* 3 - long press
* 4 - released after long press
*/
int changeButtonStatus(int butPin) {
// Event
int event = 0;
// Current button status
int currentButtonClick = digitalRead(butPin);
// Current time
unsigned long timeButton = millis();
switch(currentButtonStatus) {
case 0:
// button has not been pressed
if(currentButtonClick) {
// fix button click
currentButtonStatus = 1;
currentButtonStatusStart1 = millis();
} else {
// button is not pressed
}
break;
case 1:
// button is pressed for the first time
if(currentButtonClick) {
// button is still pressed
if(timeButton - currentButtonStatusStart1 >= delayLongSingleClick) {
// button long press state
event = 3;
}
} else {
// button has been released
if(timeButton - currentButtonStatusStart1 < delayFalse) {
currentButtonStatus = 0;
event = 0;
} else if(timeButton - currentButtonStatusStart1 < delayLongSingleClick) {
currentButtonStatus = 2;
currentButtonStatusStart2 = millis();
} else {
// button has been released after long press
currentButtonStatus = 0;
event = 4;
}
}
break;
case 2:
if(currentButtonClick) {
// if the button has been pressed for the second time
// check how long the button has been released
if(timeButton - currentButtonStatusStart2 < delayFalse) {
currentButtonStatus = 1;
} else {
// fix second press
currentButtonStatus = 3;
currentButtonStatusStart3 = millis();
}
} else {
// if the button is still released
// check for the single click
if(timeButton - currentButtonStatusStart2 > delayDeltaDoubleClick) {
// button has been released for too long, fix single click
currentButtonStatus = 0;
event = 1;
}
}
break;
case 3:
// confirm double click
if(currentButtonClick) {
// button is still pressed
// wait for the button to be released
} else {
// button has been released
// check for the debounce
if(timeButton - currentButtonStatusStart3 < delayFalse) {
// button has been released too early, probably it's a debounce
} else {
// fix double click
event = 2;
currentButtonStatus = 0;
}
}
break;
}
return event;
}
我会感激，如果你能帮我找出什么可能是问题。
*您的问题：*您正在通过覆盖*共享变量（例如'currentButtonStatus'）将有关不同*引脚*的事件混合在一起。 * /回答*除非您希望我们也提供正确的实施。 –