混合和匹配RxJava订阅线程

Question

是否有可能在RxJava中混合和匹配调度程序线程。基本上我想在Android上做类似下面的事情。

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在同一订阅中可能吗？

Answer 1

是的，当你完全理解逻辑之后，它是可能的，而且非常容易。但你可能混淆了一下observeOn（）和subscribeOn（）运算符:)

uiObservable 
    .switchMap(o -> return anotherUIObservable) 
    .subscribeOn(AndroidSchedulers.mainThread()) // means that the uiObservable and the switchMap above will run on the mainThread. 

    .switchMap(o -> return networkObservable) //this will also run on the main thread 

    .subscribeOn(Schedulers.newThread()) // this does nothing as the above subscribeOn will overwrite this 

    .observeOn(AndroidSchedulers.mainThread()) // this means that the next operators (here only the subscribe will run on the mainThread 
    .subscribe(result -> doSomething(result)) 

也许这是你想要什么：

uiObservable 
    .switchMap(o -> return anotherUIObservable) 
    .subscribeOn(AndroidSchedulers.mainThread()) // run the above on the main thread 

    .observeOn(Schedulers.newThread()) 
    .switchMap(o -> return networkObservable) // run this on a new thread 

    .observeOn(AndroidSchedulers.mainThread()) // run the subscribe on the mainThread 
    .subscribe(result -> doSomething(result)) 

奖励：我已经写a post这些运营商，希望它有助于