1
似乎一切都在我的代码中检查;我已经检查了不同函数的语法,并且所有内容似乎都在检查中,但我似乎仍然在XCode中收到错误'No Matching Function for Call to'MyInput'',没有任何解释。任何帮助,将不胜感激!代码如下。没有匹配的函数调用 - Xcode?
#include <iostream>
#include <iomanip>
using namespace std;
typedef char ShortName[10];
typedef char LongName[17];
typedef char IDarray[6];
void MyInput(ShortName [],char [], LongName [], float [],int [],IDarray [],int&);
int main(int argc, const char * argv[])
{
const int max = 7;
const int ConstStateTax = .05;
const int ConstFedTax = .15;
const int ConstUnionFees = .02;
ShortName firstname[max];
char MI[max];
LongName lastname[max];
float hourrate[max];
int OTHours[max];
float Gross[max];
float Overtime[max];
float GGross[max];
float StateTax[max];
float FedTax[max];
float UnionFees[max];
IDarray EmployeeID[max];
float Net[max];
MyInput(firstname,MI,lastname,hourrate,OTHours,EmployeeID,max);
return 0;
}
void MyInput(ShortName firstname[],char MI[],LongName lastname[],float hourrate[],int OTHours[],IDarray EmployeeID[],int &max)
{
for(int i = 0;i<=max;i++)
{
cout << "Please enter the first name of employee #" << i+1 << ": ";
cin >> firstname[i];
cout << "Please enter the middle initial of employee #" << i+1 << ": ";
cin >> MI[i];
cout << "Please enter the last name of Employee #" << i+1 << ": ";
cin >> lastname[i];
cout << "What is the ID number of Employee #" << i+1 << "? (6 letters or numbers only): ";
cin >> EmployeeID[i];
cout << "What is the hourly rate of employee #" << i+1 << "? ";
cin >> hourrate[i];
while (hourrate[i] < 0)
{
cout << "Invalid rate, please try again: ";
cin >> hourrate[i];
}
cout << "How many overtime hours does employee #" << i+1 << " have? ";
cin >> OTHours[i];
while(OTHours[i]<0 || OTHours[i] >20)
{
cout << "Invalid Overtime Hours, please re-enter: ";
cin >> OTHours[i];
}
}
}
解决了它,谢谢你! – Codetographer 2014-10-02 17:02:02
它为dladdr((const void *)func,&test)工作,其中“func”是一个带“std :: string”返回的函数。 – GLCraft 2017-07-12 14:02:32