2011-08-23 34 views

回答

4

大约

using System.Linq; 

class Person 
{ 
    public int Id; 
    public string Name; 
} 

class Address 
{ 
    public int Id; 
    public string Street; 
} 

class PersonAddress 
{ 
    public int PersonId, AddressId; 
} 

public class Program 
{ 
    public static void Main(string[] args) 
    { 
     var personList = new [] 
     { 
      new Person { Id = 1, Name = "Pete" }, 
      new Person { Id = 2, Name = "Mary" }, 
      new Person { Id = 3, Name = "Joe" } 
     }; 

     var addressList = new [] 
     { 
      new Address { Id = 100, Street = "Home Lane" }, 
      new Address { Id = 101, Street = "Church Way" }, 
      new Address { Id = 102, Street = "Sandy Blvd" } 
     }; 

     var relations = new [] 
     { 
      new PersonAddress { PersonId = 1, AddressId = 101 }, 
      new PersonAddress { PersonId = 3, AddressId = 101 }, 

      new PersonAddress { PersonId = 2, AddressId = 102 }, 
      new PersonAddress { PersonId = 2, AddressId = 100 } 
     }; 

     var joined = 
        from par in relations 
        join p in personList 
         on par.PersonId equals p.Id 
        join a in addressList 
         on par.AddressId equals a.Id 
        select new { Person = p, Address = a }; 

     foreach (var record in joined) 
      System.Console.WriteLine("{0} lives on {1}", 
            record.Person.Name, 
            record.Address.Street); 
    } 
} 

输出:

Pete lives on Church Way 
Mary lives on Sandy Blvd 
Mary lives on Home Lane 
Joe lives on Church Way 
+0

与处理的数据(可替代的方式更新了许多性能扩展能力更强,并且支持更新他们好了很多,取得了数据类非值类型因为这个原因) – sehe

+0

非常感谢!现在我要弄清楚如何连接到DataSource,将数据绑定到列表视图,并访问aspx页面 – Donnie

+0

中的属性,您将“可以”始终在SQL Server中建立连接,并且当您生成DBML文件时,它将生成为你加入。然后你可以通过Person.Address.Street访问一个人的地址。上述方法是一种很好的解耦方法,EF Code First最有效。 –