红宝石 - 合并两个数组，并删除具有重复

Question

值I有两个阵列

a = [1, 2, 3, 4, 5] 

b = [2, 4, 6] 

我想合并这两个阵列，然后删除与其它阵列相同的值。结果应该是：

c = [1, 3, 5, 6] 

我试过减去两个数组，结果是[1,3,5]。我也想从第二个数组中得到第二个数组的值，它们没有从第一个数组中重复。

Answer 1

您可以执行以下操作！

# Merging 
c = a + b 
=> [1, 2, 3, 4, 5, 2, 4, 6] 
# Removing the value of other array 
# (a & b) is getting the common element from these two arrays 
c - (a & b) 
=> [1, 3, 5, 6] 

德米特里的评论也一样，虽然我想到了我的想法独立。

Answer 2

这个怎么样。

(a | b) 
=> [1, 2, 3, 4, 5, 6] 
(a & b) 
=> [2, 4] 

(a | b) - (a & b) 
[1, 3, 5, 6] 

Answer 3

使用Array#uniq。

a = [1, 3, 5, 6] 
b = [2, 3, 4, 5] 

c = (a + b).uniq 
=> [1, 3, 5, 6, 2, 4]