我与ROUND函数基本为LibreOffice中遇到的一个问题: Function Round(dNumber As Double, iDecimals As Integer) As Variant
Dim oRound As Object
Dim vArgs(1 to 2) As Variant
oRound = createUnoService("com.sun
我有一列数字,需要保留为数字,但将长度限制为20个字符。 Sub casecheck()
Dim myString As String
Dim newString As String
Dim char As Variant
'replace all special characters with nothing
Const SpecialCharacters As String =
我将通过实例解释我的问题: >>> #In this case, I get unwanted result
>>> k = 20685671025767659927959422028/2580360422
>>> k
8.016582043889239e+18
>>> math.floor(k)
8016582043889239040
>>> #I dont want this to
我已经花了很长时间,试图在java中转换数字1.2846202978398e + 19,没有任何运气。目前我正在试图做的(long)Double.parseDouble(hashes),但是这给了9223372036854775807,这显然是不正确的。实际数字应该看起来像这样12855103593745000000. 使用int val = new BigDecimal(stringValue)