2012-07-25 65 views
2

示例代码单击事件:简单的上下文菜单jQuery的离开与细胞

这个弹出打开后用鼠标右键单击链接..但同样的结果要点击在该网站进行任何细胞后得到的。

$(function(){ 
    $.contextMenu({ 
     selector: '.context-menu-one', 
     callback: function(key, options) { 
      var m = "clicked: " + key; 
      window.console && console.log(m) || alert(m); 
     }, 
     items: { 
      "edit": {name: "Edit", icon: "edit"}, 
      "cut": {name: "Cut", icon: "cut"}, 
      "copy": {name: "Copy", icon: "copy"}, 
      "paste": {name: "Paste", icon: "paste"}, 
      "delete": {name: "Delete", icon: "delete"}, 
      "sep1": "---------", 
      "quit": {name: "Quit", icon: "quit"} 
     } 
    }); 

    $('.context-menu-one').on('click', function(e){ 
     console.log('clicked', this); 
    }) 
}); 

<div class="context-menu-one box menu-1"> 
    <strong>right click me</strong> 
</div> 
+0

PLZ需要快速重播 – Test 2012-07-25 13:01:31

+0

PLZ,回答你的问题出于善意的。一旦有人有答案,回复就会发生。 – 2012-07-25 13:02:50

+0

需要修改此代码 – Test 2012-07-25 13:05:45

回答

1

要使整个页面脚本火,改变你的选择:

selector: 'body',