按照this answer,这是因为幂乘的实现有一些开销,乘法不是。然而,随着指数的增加,初始乘法会变得越来越慢。经验证明:
In [3]: x = np.random.rand(1e6)
In [15]: %timeit x**2
100 loops, best of 3: 11.9 ms per loop
In [16]: %timeit x*x
100 loops, best of 3: 12.7 ms per loop
In [17]: %timeit x**3
10 loops, best of 3: 132 ms per loop
In [18]: %timeit x*x*x
10 loops, best of 3: 27.2 ms per loop
In [19]: %timeit x**4
10 loops, best of 3: 132 ms per loop
In [20]: %timeit x*x*x*x
10 loops, best of 3: 42.4 ms per loop
In [21]: %timeit x**10
10 loops, best of 3: 132 ms per loop
In [22]: %timeit x*x*x*x*x*x*x*x*x*x
10 loops, best of 3: 137 ms per loop
In [24]: %timeit x**15
10 loops, best of 3: 132 ms per loop
In [25]: %timeit x*x*x*x*x*x*x*x*x*x*x*x*x*x*x
1 loops, best of 3: 212 ms per loop
注幂停留的时间除外x**2
情况下,我怀疑或多或少的恒定,是特例,而乘法变得越来越慢。看来你可以利用这个来获得更快的整数幂...例如:
In [26]: %timeit x**16
10 loops, best of 3: 132 ms per loop
In [27]: %timeit x*x*x*x*x*x*x*x*x*x*x*x*x*x*x*x
1 loops, best of 3: 225 ms per loop
In [28]: def tosixteenth(x):
....: x2 = x*x
....: x4 = x2*x2
....: x8 = x4*x4
....: x16 = x8*x8
....: return x16
....:
In [29]: %timeit tosixteenth(x)
10 loops, best of 3: 49.5 ms per loop
看来,你可以通过拆分任意整数到的两个大国的总和,计算每两个功率一般应用该技术如上所述,且求和:
In [93]: %paste
def smartintexp(x, exp):
result = np.ones(len(x))
curexp = np.array(x)
while True:
if exp%2 == 1:
result *= curexp
exp >>= 1
if not exp: break
curexp *= curexp
return result
## -- End pasted text --
In [94]: x
Out[94]:
array([ 0.0163407 , 0.57694587, 0.47336487, ..., 0.70255032,
0.62043303, 0.0796748 ])
In [99]: x**21
Out[99]:
array([ 3.01080670e-38, 9.63466181e-06, 1.51048544e-07, ...,
6.02873388e-04, 4.43193256e-05, 8.46721060e-24])
In [100]: smartintexp(x, 21)
Out[100]:
array([ 3.01080670e-38, 9.63466181e-06, 1.51048544e-07, ...,
6.02873388e-04, 4.43193256e-05, 8.46721060e-24])
In [101]: %timeit x**21
10 loops, best of 3: 132 ms per loop
In [102]: %timeit smartintexp(x, 21)
10 loops, best of 3: 70.7 ms per loop
它速度快两小甚至权力:
In [106]: %timeit x**32
10 loops, best of 3: 131 ms per loop
In [107]: %timeit smartintexp(x, 32)
10 loops, best of 3: 57.4 ms per loop
但随着指数变大变慢:
In [97]: %timeit x**63
10 loops, best of 3: 133 ms per loop
In [98]: %timeit smartintexp(x, 63)
10 loops, best of 3: 110 ms per loop
而对于大型最坏情况下并不快:
In [115]: %timeit x**511
10 loops, best of 3: 135 ms per loop
In [114]: %timeit smartintexp(x, 511)
10 loops, best of 3: 192 ms per loop
也许整数与浮点数计算? –
@RohitJain我不认为这是一个特别有用的链接。被接受的答案是“使用numpy”,问题是关于纯Python代码,而不是NumPy。 – delnan
@delnam忘记接受的答案看看顶部投票的答案。 – cmd