第二次scanf不会运行，程序只是终止。 C

Question

该程序仅适用于1个printf scanf对。当我添加第二对并运行程序时，它允许我输入第一个变量。但跳过第二个并终止程序。怎么了？

#include <stdio.h> 

//Version A-1.0 

main 
{ 
    //Variables 
    int HQ; 
    char additionalbuilding; 

    //Prompt user to specify a HQ level 
    printf("Specify a HQ level. (1-20): "); 
    scanf("%d",&HQ); 
    printf("Would you like another building? (y/n): "); 
    scanf("%c",&additionalbuilding); 
} 

Answer 1

这是因为从输入的整数前面\ n的buffer.Use停留在getchar函数scanf函数来摆脱它

printf("Specify a HQ level. (1-20): "); 
scanf("%d",&HQ); 
getchar(); 
printf("Would you like another building? (y/n): "); 
scanf("%c",&additionalbuilding);