Oracle - 在查询结果

Question

之间插入新行

我在这里有一个棘手的任务。这里的样本数据：

create table incidents (
incident_id number, 
region_id varchar2(100 char), 
tasktype varchar2(100 char), 
department_from varchar2(100 char), 
department_to varchar2(100 char), 
routing_date date, 
failure_from date, 
failure_to date, 
incident_acception_date date, 
incident_resolve_date date 
); 

Insert into incidents (incident_id,region_id,Tasktype,department_from,department_to,routing_date,failure_from,failure_to,incident_acception_date,incident_resolve_date) values (1,'RE2','Task','Group1','Group2',to_date('10.04.2015 23:54:21','dd.mm.yyyy hh24:mi:ss'),to_date('26.03.2015 22:00:00','dd.mm.yyyy hh24:mi:ss'),to_date('13.04.2015 18:25:00','dd.mm.yyyy hh24:mi:ss'),to_date('26.03.2015 22:32:00','dd.mm.yyyy hh24:mi:ss'),to_date('13.04.2015 18:50:07','dd.mm.yyyy hh24:mi:ss')); 
Insert into incidents (incident_id,region_id,Tasktype,department_from,department_to,routing_date,failure_from,failure_to,incident_acception_date,incident_resolve_date) values (1,'RE2','Task','Group2','Group3',to_date('13.04.2015 07:19:05','dd.mm.yyyy hh24:mi:ss'),to_date('26.03.2015 22:00:00','dd.mm.yyyy hh24:mi:ss'),to_date('13.04.2015 18:25:00','dd.mm.yyyy hh24:mi:ss'),to_date('26.03.2015 22:32:00','dd.mm.yyyy hh24:mi:ss'),to_date('13.04.2015 18:50:07','dd.mm.yyyy hh24:mi:ss')); 
Insert into incidents (incident_id,region_id,Tasktype,department_from,department_to,routing_date,failure_from,failure_to,incident_acception_date,incident_resolve_date) values (2,'RE2','Task','Group1','Group4',to_date('01.04.2015 21:26:16','dd.mm.yyyy hh24:mi:ss'),to_date('30.03.2015 13:00:00','dd.mm.yyyy hh24:mi:ss'),to_date('02.04.2015 09:30:00','dd.mm.yyyy hh24:mi:ss'),to_date('30.03.2015 14:09:00','dd.mm.yyyy hh24:mi:ss'),to_date('02.04.2015 10:06:13','dd.mm.yyyy hh24:mi:ss')); 
Insert into incidents (incident_id,region_id,Tasktype,department_from,department_to,routing_date,failure_from,failure_to,incident_acception_date,incident_resolve_date) values (2,'RE2','Task','Group4','UNASSIGNED',to_date('01.04.2015 22:45:14','dd.mm.yyyy hh24:mi:ss'),to_date('30.03.2015 13:00:00','dd.mm.yyyy hh24:mi:ss'),to_date('02.04.2015 09:30:00','dd.mm.yyyy hh24:mi:ss'),to_date('30.03.2015 14:09:00','dd.mm.yyyy hh24:mi:ss'),to_date('02.04.2015 10:06:13','dd.mm.yyyy hh24:mi:ss')); 
Insert into incidents (incident_id,region_id,Tasktype,department_from,department_to,routing_date,failure_from,failure_to,incident_acception_date,incident_resolve_date) values (2,'RE2','Task','UNASSIGNED','Group2',to_date('01.04.2015 22:45:32','dd.mm.yyyy hh24:mi:ss'),to_date('30.03.2015 13:00:00','dd.mm.yyyy hh24:mi:ss'),to_date('02.04.2015 09:30:00','dd.mm.yyyy hh24:mi:ss'),to_date('30.03.2015 14:09:00','dd.mm.yyyy hh24:mi:ss'),to_date('02.04.2015 10:06:13','dd.mm.yyyy hh24:mi:ss')); 
Insert into incidents (incident_id,region_id,Tasktype,department_from,department_to,routing_date,failure_from,failure_to,incident_acception_date,incident_resolve_date) values (3,'RE2','Information','UNASSIGNED','Group1',to_date('01.04.2015 07:31:27','dd.mm.yyyy hh24:mi:ss'),to_date('01.04.2015 06:00:00','dd.mm.yyyy hh24:mi:ss'),to_date('11.06.2015 07:06:00','dd.mm.yyyy hh24:mi:ss'),to_date('01.04.2015 07:20:00','dd.mm.yyyy hh24:mi:ss'),to_date('16.06.2015 14:17:25','dd.mm.yyyy hh24:mi:ss')); 
commit; 

它看起来如下：

我的目标是为每一个事件

• 一个新的先行记录和

• 一个新的成功记录。

它需要在没有临时表的情况下完成（WITH AS会好的）。

所需的输出如下所示：

箭头示出，其中对于新列的数据取自。 规则：

• 如果第一个记录包含DEPARTMENT_FROM =“未分配”，新前述记录将DEPARTMENT_FROM =“1级代理”，否则DEPARTMENT_FROM =“未分配”。

但我认为这些照片使它很清楚。

这怎么可能实现？

非常感谢您的高级！

Answer 1

表中的行没有任何隐式排序，如果您在SELECT语句中没有提供ORDER BY子句，数据库可以按照它想要的顺序自由返回行，因为您还没有告诉它如何订购返回的行。没有ORDER BY子句，没有“第一行”，也没有“最后一行”。如果你想要订购的东西，你需要有一个字段（我经常有一个名为SORT_ORDER），它定义了行应该如何排序。因此，如果我已经有了一行SORT_ORDER = 1，那么我可以通过插入一个SORT_ORDER = 0的新行来添加一个“之前”行。同样，我可以通过插入一个新行并添加SORT_ORDER = 2来添加一个“后续”行但是当查询这张表时，我需要记住指定ORDER BY SORT_ORDER。

好运。

Answer 2

我尝试给你一个例子，你可以适应你的需求。我使用分层查询来制定“预先”和“成功”。通过联盟，我将他们加入到原始数据集中。我用WITH来建立示例数据。希望有所帮助！

with 
    incidents as (
     select 1 as id, 'group 1' as "from", 'group 2' as "to" from dual 
     union 
     select 1 as id, 'group 2' as "from", 'group 3' as "to" from dual 
     union 
     select 2 as id, 'UNASSIGNED' as "from", 'G1' as "to" from dual 
    ) 
select 0  as rwn, 
     id, 
     ( 
     case 
      when "from" = 'UNASSIGNED' 
      then '1st-Level-Agent' 
      else 'UNASSIGNED' 
     end 
     )  as "from", 
     "from" as "to" 
    from (select t.*, level as lvl, connect_by_isleaf as leaf 
      from incidents t 
     connect by prior "from" = "to") 
where lvl = 1 
    and leaf = 1 
union 
select rownum as rwn, t2.* from incidents t2 
union 
select 1000  as rwn, 
     id, 
     "to"  as "from", 
     'RESOLVED' as "to" 
    from (select t.*, level as lvl, connect_by_isleaf as leaf 
      from incidents t 
     connect by "from" = prior "to") 
where lvl = 1 
    and leaf = 1 
order by 2,1