随机HSV颜色

Question

我试图获得随机HSV颜色，然后将其转换为RGB使用。有没有人有任何想法，我该如何做到这一点？谢谢，山姆。我到目前为止：第一种方法用指定的值将HSV转换为RGB，第二种方法用于获得随机颜色。

public static float[] HSVtoRGB(float h, float s, float v) { 
    float m, n, f; 
    int i; 

    float[] hsv = new float[3]; 
    float[] rgb = new float[3]; 

    hsv[0] = h; 
    hsv[1] = s; 
    hsv[2] = v; 

    if (hsv[0] == -1) { 
     rgb[0] = rgb[1] = rgb[2] = hsv[2]; 
     return rgb; 
    } 
    i = (int) (Math.floor(hsv[0])); 
    f = hsv[0] - i; 
    if (i % 2 == 0) { 
     f = 1 - f; // if i is even 
    } 
    m = hsv[2] * (1 - hsv[1]); 
    n = hsv[2] * (1 - hsv[1] * f); 
    switch (i) { 
     case 6: 
     case 0: 
      rgb[0] = hsv[2]; 
      rgb[1] = n; 
      rgb[2] = m; 
      break; 
     case 1: 
      rgb[0] = n; 
      rgb[1] = hsv[2]; 
      rgb[2] = m; 
      break; 
     case 2: 
      rgb[0] = m; 
      rgb[1] = hsv[2]; 
      rgb[2] = n; 
      break; 
     case 3: 
      rgb[0] = m; 
      rgb[1] = n; 
      rgb[2] = hsv[2]; 
      break; 
     case 4: 
      rgb[0] = n; 
      rgb[1] = m; 
      rgb[2] = hsv[2]; 
      break; 
     case 5: 
      rgb[0] = hsv[2]; 
      rgb[1] = m; 
      rgb[2] = n; 
      break; 
    } 
    return rgb; 
} 

public static int randomColor() { 
    int hue = (int) (Math.random() * 6.0f); 
    int saturation = (int) (Math.random()); 
    int brightness = (int) (Math.random()); 

    float[] rgb = HSVtoRGB(hue, saturation, brightness); 

    int red = (int) (rgb[0] * 255.0f); 
    int green = (int) (rgb[1] * 255.0f); 
    int blue = (int) (rgb[2] * 255.0f); 

    return (red << 16) | (green << 8) | blue; 
} 

Answer 1

您可以使用java.awt.Color.RGBtoHSB(...)您可以找到相关的文档在这里：http://docs.oracle.com/javase/1.4.2/docs/api/java/awt/Color.html

然后，它只是变得微不足道生成一个随机的颜色。

int red = (int) (Math.random() * 256) 
int green = (int) (Math.random() * 256) 
int blue = (int) (Math.random() * 256) 

然后直接转换。请注意，在同一个类中还有一个HSBtoRGB(...)函数。