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我有一个投票应用程序的graphql环境，有用户，民意调查和投票。 我在我的主要查询架构，在我的应用程序中的所有民意调查查询（限制等选项...），我也有一个民意测验字段为每个用户，我希望一般所有民意调查是可以使用我自己的商业逻辑进行排序（例如大多数投票，最近的等等），我不想为每个投票领域定义排序逻辑，并且将类型排序为一般。 这怎么办？GraphQL排序自定义类型
这是我的代码，我目前只使用模拟数据库进行测试，并找出我需要的模式。现在到GQL。
userType = new GraphQLObjectType({
name: 'User',
description: 'Registered user',
fields: (() => ({
id: {
type: new GraphQLNonNull(GraphQLID)
},
email: {
type: GraphQLString
},
password: {
type: GraphQLString
},
username: {
type: GraphQLString
},
polls: { // this should be sortable
type: new GraphQLList(pollType),
resolve: user => db.getUserPolls(user.id)
},
votes: {
type: new GraphQLList(voteType),
resolve: user => db.getUserVotes(user.id)
}
})),
resolve: id => db.getUsers()[id]
});
pollType = new GraphQLObjectType({
name: 'Poll',
description: 'Poll which can be voted by registered users',
fields:() => ({
id: {
type: new GraphQLNonNull(GraphQLID)
},
title: {
type: GraphQLString
},
options: {
type: new GraphQLList(GraphQLString),
},
votes: {
type: new GraphQLList(voteType),
resolve: poll => db.getPollVotes(poll.id)
},
author: {
type: userType,
resolve: poll => db.getPollAuthor(poll.id)
},
timestamp: {
type: GraphQLDate
}
})
});
voteType = new GraphQLObjectType({
name: 'Vote',
description: 'User vote on a poll',
fields:() => ({
id: {
type: new GraphQLNonNull(GraphQLID)
},
user: {
type: userType,
resolve: vote => db.getVoteUser(vote.id)
},
poll: {
type: pollType,
resolve: vote => db.getVotePoll(vote.id)
},
vote: {
type: GraphQLInt
},
timestamp: {
type: GraphQLDate
}
})
});
let schema = new GraphQLSchema({
query: new GraphQLObjectType({
name: 'Query',
fields:() => ({
user: {
type: userType,
args: {
id: {
type: new GraphQLNonNull(GraphQLID)
}
},
resolve: (root, {id}) => db.getUsers()[id]
},
polls: { //this should also be sorted
type: new GraphQLList(pollType),
resolve:() => db.getPolls()
},
votes: {
type: new GraphQLList(voteType),
resolve:() => db.getVotes()
}
})
})
});