错误＃29预计C中的表达

Question

代码片段：

#define ATT_UUID_SIZE     16 

#define ATT_BT_UUID_SIZE     2 

typedef unsigned char uint8; 

typedef struct 
{ 
    uint8 len;     //!< Length of UUID (2 or 16) 
    uint8 uuid[ATT_UUID_SIZE]; //!< 16 or 128 bit UUID 
} attAttrType_t; 

typedef struct 
{ 
    uint16 startHandle; 
    uint16 endHandle; 
    attAttrType_t type; 
} attReadByTypeReq_t; 

attReadByTypeReq_t req; 
req.startHandle=svcStartHdl; 
req.endHandle=svcEndHdl; 
req.type.len=ATT_BT_UUID_SIZE; 
req.type.uuid[ATT_BT_UUID_SIZE]={0xAD,0x2B}; 

=>它说错误＃29时，我给你写0xAD和0x2B访问为的uuid我能怎么做？错

Answer 1

req.type.uuid[ATT_BT_UUID_SIZE]={0xAD,0x2B}; 

此行不正确。 uuid [xxx]的uuid是一个数组地址，不能通过'='方法赋值。这样做：

req.type.uuid[0] = 0xAD; 
req.type.uuid[1] = 0x2B; 

或像这样：

memcpy(req.type.uuid, YOUR_VALUE, ATT_BT_UUID_SIZE);