2017-09-14 45 views
1

我创建一个Python脚本解析从https://vulners.com/api/v3/search/stats/Python的JSON unhashable类型:“字典”

JSON响应我在我的.py下面的代码:

import json 
import requests 

response = requests.get('https://vulners.com/api/v3/search/stats/') 
vuln_set = json.loads(response.text) 

vuln_type = vuln_set['data']['type_results'] 
vuln_bulletinfamily = vuln_set['data']['type_results'][vuln_type]['bulletinFamily'] 
vuln_name = vuln_set['data']['type_results'][vuln_type]['displayName'] 

print("Type: " + vuln_type) 
print("Bulletin Family: " + vuln_bulletinfamily) 
print("Name: " + vuln_name) 

我需要得到藏汉vuln_type随着孩子的信息(vuln_bulletinfamily & vuln_name) 从一个JSON响应摘录:

"data": { 
"type_results": { 
    "aix": { 
    "lastUpdated": [], 
    "bulletinFamily": "unix", 
    "displayName": "IBM AIX", 
    "lastrun": "2017-09-14T14:04:56", 
    "count": 110, 
    "workTime": "0:00:10.983795" 
    }, 
    "akamaiblog": { 
    "lastUpdated": [], 
    "bulletinFamily": "blog", 
    "displayName": "Akamai Blog", 
    "lastrun": "2017-09-14T10:38:52", 
    "count": 1463, 
    "workTime": "0:00:00.358691" 
    }, 
    "amazon": { 
    "lastUpdated": [], 
    "bulletinFamily": "unix", 
    "displayName": "Amazon Linux AMI", 
    "lastrun": "2017-09-14T14:17:40", 
    "count": 889, 
    "workTime": "0:00:01.839594" 
    }, 

我GE拟合类型错误的错误:unhashable类型:“字典”

回溯:

Traceback (most recent call last): 
File "test.py", line 9, in <module> 
vuln_bulletinfamily = vuln_set['data']['type_results'][vuln_type]['bulletinFamily'] 
TypeError: unhashable type: 'dict' 
+1

密钥必须是可散列的。作为一般规则,只有不可变对象(字符串,整数,浮点数,frozensets,不可变元组)是可散列的(尽管例外是可能的)。 – amrit

+0

我已将traceback添加到上述 – Luke

+1

您正在传递一个字典,以查找为字典密钥。 'vuln_type = vuln_set ['data'] ['type_results']',它是一个字典尝试打印它。您需要从该词典中选择一个可能的键来继续深入到“bulletinFamily”的层次结构中。目前还不清楚你想要做什么,也许你打算迭代'type_results'字典中的项目? –

回答

1

在回溯线,下一行和打印的第一行,你试图访问一个字典type_resultsvuln_type与一个也是字典的关键。 您需要循环使用密钥,例如: -

import json 
import requests 

response = requests.get('https://vulners.com/api/v3/search/stats/') 
vuln_set = json.loads(response.text) 

vuln_type = vuln_set['data']['type_results'] 
for k in vuln_type : 
    vuln_bulletinfamily = vuln_set['data']['type_results'][k]['bulletinFamily'] 
    vuln_name = vuln_set['data']['type_results'][k]['displayName'] 

    print("Type: " + k) 
    print("Bulletin Family: " + vuln_bulletinfamily) 
    print("Name: " + vuln_name) 
+0

工作正常!几天前我刚刚开始使用python,来自PHP – Luke

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