我有一个SVG,我使用过滤器在黑色背景上使用多重混合来混合白色形状。由于我正在使用乘法,所以我希望白色的形状根本不会出现,但事实并非如此。在这个例子中我画在它自己的滤波器的正方形,然后一个较小的圆(也在其自身的滤波器):SVG:使用feBlend多重混合摆脱形状轮廓
http://jsfiddle.net/mugwhump/SwcjL/2/
然而,有微弱的,像素宽的白色轮廓包围圈子。此轮廓的颜色和不透明度取决于用于绘制圆的颜色和不透明度。
如果我将圆移动到与正方形相同的滤镜组中,它就会消失,但不幸的是这不是一个选项。
任何想法如何摆脱这个大纲?这基本上发生在所有浏览器/渲染器中。
这里的SVG代码:
<svg contentScriptType="text/ecmascript" width="530"
xmlns:xlink="http://www.w3.org/1999/xlink" zoomAndPan="magnify"
contentStyleType="text/css" viewBox="0 0 530 530" height="530"
preserveAspectRatio="xMidYMid meet" xmlns="http://www.w3.org/2000/svg"
version="1.1">
<defs id="defs">
<!--Blend using multiply. -->
<filter color-interpolation-filters="sRGB" x="-1.0" y="-1.0" width="3.0"
xmlns:xlink="http://www.w3.org/1999/xlink" xlink:type="simple"
xlink:actuate="onLoad" height="3.0"
xlink:show="other" id="blend-square-multiply">
<feFlood result="blackness" flood-color="black"/>
<feComposite result="blackness clip" in="blackness" in2="SourceGraphic" operator="in"/>
<feColorMatrix in="SourceGraphic" values="1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0" type="matrix" result="color-trans"/>
<feBlend mode="multiply" in="blackness clip" in2="color-trans"/>
</filter>
</defs>
<!-- White square blended with multiply over black feFlood -->
<g filter="url(#blend-square-multiply)">
<g fill="white" >
<rect x="200" width="100" y="200" height="100" />
</g>
</g>
<!-- White circle blended with multiply over black feFlood
Changing stroke width does nothing, but changing fill color changes
the color of the outline (changing stroke-color does not).
The outline disappears when opacity is set to 0. -->
<g filter="url(#blend-square-multiply)">
<g fill="white" opacity="1">
<circle stroke-width="0" cx="250" cy="250" r="50"/>
</g>
</g>