MySQL：计数，分组和排序：整个表数据？

Question

我有一个表的数据：

 
id one two three four  five six 
------------------------------------------------ 
1 12  32  2  5  34  13 
2 43  12  3  33  22  17 
3 11  31  3  15  13  13 
4 43  12  52  73  29  19 
5 3  2  2  3  9  9 
6 4  1  3  7  2  19 
------------------------------------------------- 

，所以我知道如何通过与秩序一列数，组，就像这样：

select one, count(one) from table_numbers group by one order by count(one) desc

上面的查询将会给我们：

 
one  count(one) 
----------------- 
43  2 
3  1 
4  1 
11  1 
12  1 
----------------- 

那么我怎么能得到像上面的数据在一个单一的查询中的所有列？

像这样：

 
One Count(one) Two Count(two) Three Count(three) Four Count(four) 
--------------------------------------------------------------------------- 
43 2   12 2   3  3    73  1   
3 1   1 1   2  2    3  1   
4 1   2 1   52  1    5  1   
11 1   31 1   null null   7  1   
12 1   32 1   null null   15  1   
null null  null null  null null   33  1   
--------------------------------------------------------------------------- 

现在有没有办法做到在一个单一的SQL查询？可能使用连接或内联视图或其他任何东西？或者这是可能的单个查询？

[更新]我想计算每列的重复值并按降序对其进行排序。

[更新]如果你想用表数据：

 
CREATE TABLE IF NOT EXISTS `table_numbers` (
    `id` int(11) NOT NULL AUTO_INCREMENT, `one` int(2) NOT NULL, 
    `two` int(2) NOT NULL, `three` int(2) NOT NULL, 
    `four` int(2) NOT NULL, `five` int(2) NOT NULL, 
    `six` int(2) NOT NULL, PRIMARY KEY (`id`), 
    KEY `col_one` (`one`), KEY `col_two` (`two`), 
    KEY `col_three` (`three`), KEY `col_four` (`four`), 
    KEY `col_five` (`five`), KEY `col_six` (`six`) 
) ; 

INSERT INTO `table_numbers` (`id`, `one`, `two`, `three`, `four`, `five`, `six`) 
VALUES 
(1, 12, 32, 2, 5, 34, 13),(2, 43, 12, 3, 33, 22, 17),(3, 11, 31, 3, 15, 13, 13), 
(4, 43, 12, 52, 73, 29, 19),(5, 3, 2, 2, 3, 9, 9),(6, 4, 1, 3, 7, 2, 19); 

感谢的捆绑提前！

周杰伦:-)

Answer 1

简单的方法来获得科拉姆计数一个查询：

(select 'one' as col, one as item, count(one) as count from table_numbers group by one) UNION 
(select 'two', two, count(two) from table_numbers group by two) UNION 
(select 'three', three, count(three) from table_numbers group by three) UNION 
(select 'four', four, count(four) from table_numbers group by four) UNION 
(select 'five', five, count(five) from table_numbers group by five) UNION 
(select 'six', six, count(six) from table_numbers group by six) UNION 
ORDER BY col, count DESC 

这要复杂得多。如果你想在列汇总（例如3列）：

SELECT tone.item as One, tone.count as `Count(one)`, ttwo.item as Two, ttwo.count as `Count(two)`, tthree.item as Three, tthree.count as `Count(three)` 
FROM 
    (SELECT @rownumtmp:=@rownumtmp+1 as rownum 
    FROM 
    (SELECT DISTINCT col, count 
    FROM (
     (select 'one' as col, one as item, count(one) as count from table_numbers group by one) UNION 
     (select 'two', two, count(two) from table_numbers group by two) UNION 
     (select 'three', three, count(three) from table_numbers group by three)) tmp) tmp2, 
    (SELECT @rownumtmp:=0) r) tmp2 LEFT OUTER JOIN 
    (SELECT @rownum1:=@rownum1+1 as rownum, item, count FROM (SELECT one as item, count(one) as count from table_numbers group by one ORDER BY count DESC, one) d, (SELECT @rownum1:=0) r) tone ON tmp2.rownum=tone.rownum LEFT OUTER JOIN 
    (SELECT @rownum2:=@rownum2+1 as rownum, item, count FROM (SELECT two as item, count(two) as count from table_numbers group by two ORDER BY count DESC, two) d, (SELECT @rownum2:=0) r) ttwo ON tmp2.rownum=ttwo.rownum LEFT OUTER JOIN 
    (SELECT @rownum3:=@rownum3+1 as rownum, item, count FROM (SELECT three as item, count(three) as count from table_numbers group by three ORDER BY count DESC, three) d, (SELECT @rownum3:=0) r) tthree ON tmp2.rownum=tthree.rownum 
WHERE tone.item IS NOT NULL OR ttwo.item IS NOT NULL OR tthree.item IS NOT NULL 

结果的以上查询将如下所示：

 
One Count(one) Two Count(two) Three Count(three) 
----------------------------------------------------- 
43 2   12 2   3  3    
3 1   1 1   2  2  
4 1   2 1   52  1   
11 1   31 1   null null    
12 1   32 1   null null     
------------------------------------------------------ 

Answer 2

你碰巧这个意思？：

select one, two, three, four, five, six, count(1) 
from table_numbers group by one, two, three, four, five, six 
order by count(1) desc 

你试图寻找重复？

Answer 3

我怀疑在单个查询中这样做的可能性！ 执行时，查询只会遍历一次表格。在您的情况下，它需要计算多个列的 。

Answer 4

您的意思是？

SELECT 
    one AS val, COUNT(*) AS c 
FROM ( 
    SELECT one FROM table_numbers UNION ALL 
    SELECT two FROM table_numbers UNION ALL 
    SELECT three FROM table_numbers UNION ALL 
    SELECT four FROM table_numbers UNION ALL 
    SELECT five FROM table_numbers UNION ALL 
    SELECT six FROM table_numbers 
) x GROUP BY one ORDER BY c DESC; 

Answer 5

我看到可以完成的唯一方法是...将数据从表中导出为一个长整数的字符串。即平面文件并将数据作为一个字段导回到新表格。编写sql语句以将重复推断到新字段并进行总计数。直到导入的数据字段为空为止。希望有所帮助。