胡安·鲁伊斯卡斯蒂利亚延长我的答案给出，打开我的眼睛为您“链接” - 表。
这是我的最后一个建议，在一个更CTE解决您的问题：
CREATE TABLE MiscValues
([docID] varchar(10) ,[rowNumber] int, [Column1] varchar(100), [Column2] varchar(100)
, [Column3] varchar(100))
;
INSERT INTO MiscValues
([docID],[rowNumber],[Column1], [Column2], [Column3])
VALUES
('D0001',1, 'PartNumber', 'X0455', NULL),
('D0001',2, 'Prio', '1', NULL),
('D0001',3, 'Plant1', NULL, NULL),
('D0001',4, 'Plant2', 'PlantB', NULL),
('D0001',5, 'Plant3', 'PlantC', NULL),
('D0001',6, 'Plant4', NULL, NULL),
('D0001',7, 'Color1', 'white', NULL),
('D0001',8, 'Color2', 'black', NULL),
('D0001',9, 'Color3', 'blue', NULL),
('D0001',10, 'Material', 'MA123', NULL),
('D0001',11, 'Length', NULL, '10.87'),
('D0002',1, 'PartNumber', 'X0326', NULL),
('D0002',2, 'Prio', '2', NULL),
('D0002',3, 'Plant1', 'PlantA', NULL),
('D0002',4, 'Plant2', NULL, NULL),
('D0002',5, 'Plant3', 'PlantC', NULL),
('D0002',6, 'Plant4', 'PlantD', NULL),
('D0002',7, 'Color1', NULL, NULL),
('D0002',8, 'Color2', 'black', NULL),
('D0002',9, 'Color3', NULL, NULL),
('D0002',10, 'Color4', 'yellow', NULL),
('D0002',11, 'Material', 'MA456', NULL),
('D0002',12, 'Length', NULL, '16.43')
;
CREATE TABLE LookUp([docID] varchar(10), [docType] varchar(100), [PartNumber] varchar(100), [internalID] varchar(100));
INSERT INTO LookUp([docID],[docType],[PartNumber], [internalID])
VALUES
('D0305415', 'docTypeSub', 'X0455', null),
('D0157632', 'docTypeMain', null, 'XY05570-XY05571'),
('D0181511', 'docTypeMain',null, 'XY05572-XY05573'),
('D0157633', 'docTypeMain', null, 'XY06380-XY06381'),
('D0156037', 'docTypeSub', 'X0326', null),
('D0151874', 'docTypeMain', null, 'XY05345');
CREATE TABLE Links ([docIDTop] varchar(10), [docIDBottom] varchar(10));
INSERT INTO Links ([docIDTop],[docIDBottom])
VALUES
('D0157632', 'D0305415'),
('D0181511', 'D0305415'),
('D0157633', 'D0305415'),
('D0151874', 'D0156037');
WITH CTE_no_nums
AS
(
SELECT docID,
CASE
WHEN PATINDEX('%[0-9]%',column1) > 0
THEN SUBSTRING(column1,0,PATINDEX('%[0-9]%',column1))
ELSE column1
END AS cols,
COALESCE(column2,column3) AS vals
FROM miscValues
WHERE column2 IS NOT NULL
OR column3 IS NOT NULL
),
CTE_Pivot
AS
(
SELECT docID,partNumber,prio,[length],material
FROM CTE_no_nums
PIVOT
(
MAX(vals) FOR cols IN (partNumber,prio,[length],material)
) pvt
),
CTE_InternalIDs AS
(
SELECT *
,STUFF
(
(SELECT ', ' + internalID
FROM LookUp AS L2
INNER JOIN Links L ON L2.docID=L.docIDTop
WHERE L2.internalID IS NOT NULL
AND L.docIDBottom=L1.docID
FOR XML PATH('')
),1,2,'') AS ConcatenatedInternalIDs
FROM LookUp AS L1
WHERE L1.internalID IS NULL
)
SELECT A.docId + ' # ' + B.vals AS [DocID # Plant],
A.docID,
A.partNumber,
A.prio,
B.vals AS Plant,
A.partNumber + '#' + A.material + '#' + A.[length] AS Identification,
A.[length],
SUBSTRING(CA.colors,0,LEN(CA.colors)) colors, --substring removes last comma
IIDs.ConcatenatedInternalIDs
FROM CTE_Pivot A
INNER JOIN CTE_no_nums B
ON A.docID = B.docID
AND B.cols = 'Plant'
INNER JOIN CTE_InternalIDs AS IIDs ON A.partNumber = IIDs.PartNumber
CROSS APPLY ( SELECT vals + ','
FROM CTE_no_nums C
WHERE cols = 'Color'
AND C.docID = A.docID
FOR XML PATH('')
) CA(colors)
;
--Clean up...
/*
DROP TABLE Links;
DROP TABLE LookUp;
DROP TABLE miscValues;
*/
上述回来了这一点：
D0001 # PlantB D0001 X0455 1 PlantB X0455#MA123#10.87 10.87 white,black,blue XY05570-XY05571, XY05572-XY05573, XY06380-XY06381
D0001 # PlantC D0001 X0455 1 PlantC X0455#MA123#10.87 10.87 white,black,blue XY05570-XY05571, XY05572-XY05573, XY06380-XY06381
D0002 # PlantA D0002 X0326 2 PlantA X0326#MA456#16.43 16.43 black,yellow XY05345
D0002 # PlantC D0002 X0326 2 PlantC X0326#MA456#16.43 16.43 black,yellow XY05345
D0002 # PlantD D0002 X0326 2 PlantD X0326#MA456#16.43 16.43 black,yellow XY05345
编辑：从这里开始，你会发现我的第一次回答（为了解胡安·鲁伊斯的回答）：
我没有绝对的把握，如果我理解正确的，你...你想为一个连接列表添加到您的查询与所有internalID项网络使用LookUp的PartNumber。
你有问题：没有隐含的排序顺序...
你的
VALUES
('D0305415', 'docTypeSub', 'X0455', null),
('D0157632', 'docTypeMain', null, 'XY05570-XY05571'),
('D0181511', 'docTypeMain',null, 'XY05572-XY05573'),
('D0157633', 'docTypeMain', null, 'XY06380-XY06381'),
('D0156037', 'docTypeSub', 'X0326', null),
('D0151874', 'docTypeMain', null, 'XY05345');
插入似乎 “绑定” 值 “XY05570-XY05571”， “XY05572-XY05573”和“XY06380-XY06381”分配给零件编号“X0455”，值“XY05345”分配给零件编号“X0326”。但这是错误的！
您可以像下面这样做
VALUES
('D0305415', 'docTypeSub', 'X0455', null),
('D0157632', 'docTypeMain', 'X0455', 'XY05570-XY05571'),
('D0181511', 'docTypeMain','X0455', 'XY05572-XY05573'),
('D0157633', 'docTypeMain', 'X0455', 'XY06380-XY06381'),
('D0156037', 'docTypeSub', 'X0326', null),
('D0151874', 'docTypeMain', 'X0326', 'XY05345');
或者你也可以添加IDENTITY列和摆弄那些internalID IS NULL之间的所有条目。
随着第（填写每一行的零件号列），你可以得到拼接列表如下：
select c.docType AS c_docTypeSub, c.docID AS C_docID, c.PartNumber AS C_PartNumber ,
b.docIDTop AS B_docIdTop, b.docIDBottom AS B_docIdBottom, a.*,
STUFF((SELECT ', ' + x.internalID
FROM LookUp AS x
WHERE x.PartNumber=c.PartNumber
FOR XML PATH(''),TYPE).value('.','nvarchar(max)'),1,2,'') AS ConcatInternalID
FROM LookUp a, Links b, LookUp c
WHERE a.docType = 'docTypeMain'
and a.docID = b.docIDTop and b.docIDBottom = c.docID
and c.docType = 'docTypeSub'
;
职高，你可以添加到您的“老查询”以及作者：
只需添加这最后的选择
[...CTEs before...]
SELECT A.docId + ' # ' + B.vals AS [DocID # Plant],
A.docID,
A.partNumber,
A.prio,
B.vals AS Plant,
A.partNumber + '#' + A.material + '#' + A.[length] AS Identification,
A.[length],
SUBSTRING(CA.colors,0,LEN(CA.colors)) colors, --substring removes last comma
STUFF((SELECT ', ' + x.internalID
FROM LookUp AS x
WHERE x.PartNumber=A.PartNumber
FOR XML PATH(''),TYPE).value('.','nvarchar(max)'),1,2,'') AS ConcatInternalID
[...FROM...]
希望我理解这一点很好，这可以帮助你......
你两个小提琴数据集似乎没有共同之处。实际上，如果您能够从MiscValues表中的PartNumber查找LookUp表中的PartNumber，我认为您的问题可以解决。重做数据，你应该能够从那里得出结论。同样，如果LookUp或Links中的docID字段与Document或MiscValues中的docID匹配，您的问题就解决了。如果情况并非如此，则您没有关系数据，这是不可能的。 –
嗨，托尼，如果你投票赞成有效的答案并接受帮助你解决问题的答案，thx会很好！ – Shnugo