我使用带有动态创建列的数据透视表来创建按月计算操作的报表。在动态查询中是一个涉及三列的CROSS APPLY。这导致我的总数比他们应该多三倍。我目前正在破解一个解决方案,将计数除以三,以得到正确的答案。任何人都可以帮助我想出一个更优雅的解决方案来解决这个问题吗?SQL数据透视表交叉应用于计数结果
编辑:我使用SQL Server 2008R2
鉴于此数据集(它实际上是一个看法,但我不觉得这是明智的做法是重新创建所以整个架构):
CREATE TABLE vw_ActionsReport
([CID] int, [MitigationActionID] int, [Approved] int, [Status] varchar(11), [ChangedDate] datetime, [EntryDate] varchar(7), [STATE_ABBR] varchar(2), [STATE_NAME] varchar(11), [CENSUS_NAM] varchar(12), [CIS_NAME] varchar(21), [COUNTY_NAM] varchar(9), [CO_FIPS] int, [REGION] int, [ST_FIPS] int);
INSERT INTO vw_ActionsReport
([CID], [MitigationActionID], [Approved], [Status], [ChangedDate], [EntryDate], [STATE_ABBR], [STATE_NAME], [CENSUS_NAM], [CIS_NAME], [COUNTY_NAM], [CO_FIPS], [REGION], [ST_FIPS])
VALUES
(090069, 5475, 1, 'Identified', '2012-11-27 16:21:27', '11_2012', 'CT', 'CONNECTICUT', 'OLD SAYBROOK', 'OLD SAYBROOK, TOWN OF', 'MIDDLESEX', 09007, 01, 09),
(090069, 5476, 1, 'In Progress', '2012-11-27 16:21:27', '11_2012', 'CT', 'CONNECTICUT', 'OLD SAYBROOK', 'OLD SAYBROOK, TOWN OF', 'MIDDLESEX', 09007, 01, 09),
(090012, 6687, 1, 'Identified', '2013-04-02 16:14:03', '4_2013', 'CT', 'CONNECTICUT', 'NORWALK', 'NORWALK, CITY OF', 'FAIRFIELD', 09001, 01, 09),
(090008, 6993, 1, 'Identified', '2013-06-20 15:18:38', '6_2013', 'CT', 'CONNECTICUT', 'GREENWICH', 'GREENWICH, TOWN OF', 'FAIRFIELD', 09001, 01, 09),
(090019, 17000, 0, 'Identified', '2013-11-26 11:46:14', '11_2013', 'CT', 'CONNECTICUT', 'WESTPORT', 'WESTPORT, TOWN OF', 'FAIRFIELD', 09001, 01, 09);
然后,使用下面的查询:
DECLARE @cols AS NVARCHAR(MAX),
@cols_math AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX);
SELECT @cols = STUFF
(
(
SELECT ',' + QUOTENAME(EntryDate)
FROM dbo.vw_ActionsReport
GROUP BY EntryDate,
DATEPART(YEAR, dbo.vw_ActionsReport.ChangedDate),
DATEPART(MONTH, dbo.vw_ActionsReport.ChangedDate)
ORDER BY DATEPART(YEAR, dbo.vw_ActionsReport.ChangedDate),
DATEPART(MONTH, dbo.vw_ActionsReport.ChangedDate)
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'),
1,1,''
);
SELECT @cols_math = STUFF
(
(
-- This is my hack where I divide the answer by three
SELECT ',' + QUOTENAME(EntryDate) + '/3 AS ' + QUOTENAME(EntryDate)
FROM dbo.vw_ActionsReport
GROUP BY EntryDate,
DATEPART(YEAR, dbo.vw_ActionsReport.ChangedDate),
DATEPART(MONTH, dbo.vw_ActionsReport.ChangedDate)
ORDER BY DATEPART(YEAR, dbo.vw_ActionsReport.ChangedDate),
DATEPART(MONTH, dbo.vw_ActionsReport.ChangedDate)
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)'),
1,1,''
);
SET @query = 'SELECT REGION, STATE_ABBR, [Status],' + @cols_math + ' FROM
(
SELECT REGION, STATE_ABBR, [Status], EntryDate, MitigationActionID
FROM dbo.vw_ActionsReport
CROSS APPLY
(
SELECT CAST(REGION AS VARCHAR(50)) UNION ALL
SELECT CAST(STATE_ABBR AS VARCHAR(50)) UNION ALL
SELECT CAST([Status] AS VARCHAR(50))
) c(col)
) x
PIVOT
(
COUNT(MitigationActionID)
FOR EntryDate IN (' + @cols + ')
) p ';
EXECUTE(@query);
输出应该是这样的:
+-REGION-+-STATE_ABBR-+-Status------+-11_2012-+-4_2013-+-6_2013-+-11_2013-+
| 01 | CT | Identified | 1 | 1 | 1 | 1 |
| 01 | CT | In Progress | 1 | 0 | 0 | 0 |
如果我没有在上面的查询中的评论中显示我的破解,那么输出表中的所有1都变为3。我很确定它来自CROSS APPLY,因为如果我改变CROSS APPLY中SELECTS的数量,总数也会以同样的方式改变。
我确定有更好的方法来做到这一点,但我一直不成功。我花了相当多的时间试图让DISTINCT工作,但我似乎无法使用COUNT DISTINCT从PIVOT内部工作。
如果有人能就此给我任何建议,我将不胜感激。
'COUNT(DISTINCT MitigationActionID)'是否有效? – NickyvV
@NickyvV,不,我花了很多时间试图让它工作,但找不到解决方案。我在关键字'DISTINCT'.'附近获得了错误的语法 – Matthew