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我一直试图在MATLAB中将HSV颜色空间建模到圆柱体上,但迄今为止失败了。我已经看过Modeling HSV Color Space in MATLAB,这对理解纹理贴图非常有帮助,但是当我创建一个圆柱体并将它的X,Y和Z坐标输入到surf()时,我会得到一个开放的圆柱体。有没有办法生成一个可以输入到surf()中的X,Y,Z坐标的闭合圆柱体?下面是我一直在努力,因此到目前为止,(非常类似于链接)代码:在MATLAB中对HSV颜色空间圆柱体进行建模
clear;
clc;
close all;
spSize = 500;
% linspace(a,b,s) creates a vector with s values equally spaced from a
% to b
% repmat repeats a vector x*y times
H = repmat(linspace(0,1,spSize),spSize,1); % spSize-by-spSize hues
% the spSize-value vector generated by linspace(0,1,spSize) is copied spSize times
% one under the other, resulting in a spSize x spSize array:
%
% 1 2 3 spSize
% 1 (0,0) (0,.001) (0,.002) ... (0,1)
% 2 (.001,0) (.001,.001) (.001,.002) ... (.001,1)
% ...
% spSize (1,0) (.001,1) (.002,1) ... (1,1)
S = repmat([linspace(0,1,spSize/2) linspace(1,0,spSize/2)].',1,spSize); % spSize-by-spSize saturations
% same for the saturation. Because the saturation goes from 1 to 0 to 1, we
% need first a vector that goes from 1 to 0 and a second from 0 to 1
% ([linspace(0,1,spSize/2) linspace(1,0,spSize/2)]). The ' turnes the vector in a
% row into a vector in a column.
V = repmat([ones(1,spSize/2) linspace(1,0,spSize/2)].',1,spSize); % spSize-by-spSize values
% same procedure for the intensity. Because we map a picture on a 3D-shape,
% one part of the picture has to indicate the colors of the top of the cone
% (i.e., the color wheel) - that is the first part of the vector
% (ones(1,spSize/2)) than we need to reduce the intensity to generate the rest of
% the color for the rest for the rest of the cylinder surface.
% Create an HSV image
% once all three matrices ahave been independently generated, merge them
% into a single 3-D matrix
hsvImage = cat(3,H,S,V);
% Convert it to an RGB image
C = hsv2rgb(hsvImage);
% Generate cylinder with XYZ coordinates
[X,Y,Z] = cylinder(250);
Z = Z * 400;
% Finally, plot the texture-mapped surface
figure;
surf(X,Y,Z,C,'FaceColor','texturemap','EdgeColor','none');
axis equal
耶!来自gnovice的回答! – rayryeng